The new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars. Details about pressure can be found below.
<h3>How to calculate pressure?</h3>
The pressure of a given gas can be calculated using the following formula:
P1/T1 = P2/T2
Where;
- P1 = initial pressure = 853.0 millibars
- P2 = final pressure = ?
- T1 = initial temperature = 29°C + 273 = 302K
- T2 = final temperature = 85°C + 273 = 358K
853/302 = P2/358
358 × 853 = 302P2
305374 = 302P2
P2 = 305374 ÷ 302
P2 = 1011.17 millibars
Therefore, the new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars.
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<span>2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
</span>
2 moles C6H6 -------------------- 6 moles H2O
8.73 moles C6H6 --------------- ( moles H2O)
( moles H2O) = 8.73 x 6 / 2
( moles H2O) = 52.38 / 2
= 26.19 moles of H2O
Molar mass H2O = 18.00 g/mol
1 mole -------------- 18.00 g
26.19 moles ----- ( mass of H2O)
mass of H2O = 26. 19 x 18.00 => 471.42 g of water
hope this helps!
Answer:
Percent yield = 22.8 %
Explanation:
Step 1: Data given
Numbers of moles copper = 0.0970 moles
Mass of copper(I) sulfide = 1.76 grams
Step 2: The balanced equation
2Cu + S ⇒ Cu2S
Step 3: Calculate moles of Cu2S
For 2 moles Cu we need 1 mol S to produce 1 mol Cu2S
For 0.0970 moles Cu we'll hace 0.0970 / 2 = 0.0485 moles
Step 4: Calculate mass of Cu2S
Mass Cu2s = moles Cu2S * molar mass Cu2S
Mass Cu2S = 0.0485 moles * 159.16 g/mol
Mass Cu2S = 7.72 grams
Step 5: Calculate percent yield
Percent yield = (actual yield/ theoretical mass) * 100%
Percent yield = (1.76 grams / 7.72 grams)*100%
Percent yield = 22.8 %
2 x 10 ^ 3
should be the answer ^ 3 is the exponent
Answer:
the iron is more condensed then the copper more electricity
