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Dafna1 [17]
3 years ago
15

The number of moles in 250 L of He gas at STP is ________ mol, Round to a whole number,

Chemistry
1 answer:
7nadin3 [17]3 years ago
7 0

Answer: The number of moles in 250.0 L of He at STP is 11.0 mole.

Explanation:

  • It is known that 1.0 mole of a gas at STP conditions will occupy 22.7 L.
  • To show this information: STP means that T = 0.0 °C = 273.15 K and P = 1.0 kPa =  (100/101.325) = 0.9869 atm.
  • From the ideal gas law: PV = nRT.
  • Where, P is the pressure in atm <em>(P = 1.0 atm at STP).</em>
  • V is the volume in L.
  • n is the number of moles (n = 1.0 mole).
  • R is the general gas constant (R = 0.0821 L.atm/mol.K).
  • T is the temperature in K (T = 273.15 K at STP).
  • and now we can get the volume of 1.0 mole at STP: V = nRT/P
  • V = (1.0 mole x 0.0821 L.atm/mol.K x 273.15 K) / (0.9869 atm) = 22.7 L.
  • Now, we can get the number of moles of 250.0 L of He at STP:

<em>Using cross multiplication:</em>

1.0 mole → 22.7 L

??? mole → 250.0 L

  • The number of moles in 250.0 L of He at STP = (250.0 L x 1.0 mole) / (22.7 L) = 11.01 mole ≅ 11.0 mole.
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