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3 years ago

Which compound is classified as a hydrocarbon?

Chemistry

2 answers:

Andrej [43]3 years ago

5 0

(2) butynu........................

dybincka [34]3 years ago

4 0

Answer: The correct answer is Option 2.

Explanation:

Hydrocarbons are defined as the compounds which have a covalent bond present between hydrogen and carbon atoms. For Example: $CH_4$ is a hydrocarbon. $H_2O,CO_2$ are not considered as hydrocarbons.

For the given options:

Option 1: butanal

The chemical formula for this compound is $CH_3CH_2CH_2CHO$

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

Option 2: butyne

The chemical formula for this compound is $CH\equiv CCH_2CH_3$

This is considered as a hydrocarbon because covalent bonds are present between carbon and hydrogen atoms only.

Option 3: 2-butanol

The chemical formula for this compound is $CH_3CH(OH)-CH_2CH_3$

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

Option 4: 2-butanone

The chemical formula for this compound is $CH_3C(O)-CH_2CH_3$

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

From the above information, the correct answer is Option 2.

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Explanation:

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Although the Lab guide in the question is missing a general answer within the scope of your question is provided above

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3 years ago

Click the DeltaH is an Extensive Property button within the activity, and analyze the relationship between the two reactions tha

DaniilM [7]

Answer:

∴ΔH₂ = - 12,258 KJ

Explanation:

Enthalpy:

Enthalpy is a property of a thermodynamic system. Enthalpy of a system is equal to the sum of internal energy of the system and presser times volume of the system.

The heat absorbes or releases in a closed system is the change of enthalpy of the system.

Given reactions are:

Reaction 1: C₃H₈(g)+5O₂(g)→ 3CO₂(g)+4H₂O, ΔH₁= - 2043 KJ

Reaction 2: 6C₃H₈(g)+30 O₂(g)→ 18 CO₂(g)+24 H₂O, ΔH₂=?

Take a look at reaction 1 and reaction 2, the only difference is that 1 molecule of C₃H₈ is combusted in reaction 1 and 6 molecules of C₃H₈ is combusted in reaction 2.

We can think the reaction 2 as occurring 6 different container and each containers contains 1 molecule of C₃H₈. The enthalpy is an extensive property. Total enthapy of the 6 containers is = 6×(-2043 KJ)

= - 12,258 KJ

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Select the correct answer. Elements Electronegativity aluminum (Al) 1.61 calcium (Ca) 1 carbon (C) 2.55 chlorine (Cl) 3.16 fluor

marishachu [46]

Answer: Fe - O

Explanation:

1) Start by showing the chart information in a more understandable way:

Elements ---------- Electronegativity

aluminum (Al) ----- 1.61

calcium (Ca) ------- 1

carbon (C) ---------- 2.55

chlorine (Cl) -------- 3.16

fluorine (F) --------- 4

hydrogen (H) ------ 2.2

iron (Fe) ------------- 1.83

nitrogen (N) --------- 3.04

oxygen (O) ----------- 3.44

phosphorus (P) ----- 2.19

potassium (K) -------- 0.82

silicon (Si) ------------- 1.9

sulfur (S) --------------- 2.58

2) Find the electronegativity differences for the atoms in each compound:

i) Ca – Cl: 3.16 - 1 = 2.16

ii) Fe – O: 3.44 - 1.83 = 1.61

iii) H – S: 2.58 - 2.2 = 0.38

iii= F – F = 4 - 4 = 0

3) Analysis

i) The higher the electronegativity difference between two non-metal elements, the the more the polar the covalent bond. Therefore, the bond H - S is the most polar among the non-metal - non-metal bonds listed. But 0.38 is a small difference, so this is not very polar.

ii) For metal - non-metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and so you cannot classify the bond as polar but as ionic. Therefore, Ca - Cl with 2.16 electronegativity difference is a ionic bond.

iii) The bond in Fe – O has electronegativty difference of 1.61, so it is yet covalent, and highly polar.

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