Answer is:
1) lubricant - 500 ppm by weight.
2) moisture - 50 ppm by weight.
3) non-condensable gases (air) - 150 ppm by weight.
Standard J2099 specific the maximum levels of contaminants for R134a.
ppm<span> (parts-per-million, </span>10⁻⁶) is <span>value that represents the part of a whole number in units of 1/1000000.</span>
Answer:
the number of valence electrons is equal to the atom's main group number
Explanation:
Answer: sulfur pentafluoride
Explanation:
The rules for naming of binary molecular compound :
In the given formula, the lower group number element is written first in the name and keep its element name and the higher group number is written second.
First element i.e. sulphur in the formula is named first and keep its element name.
1) Gets a prefix if there is a subscript on it such as mono for 1, di for 2, tri for 3 and so on.
Second element i.e. fluorine is named second.
1) Use the root of the element name, if it is an anion then use suffix (-ide).
2) Always use a prefix on the second element such as mono for 1, di for 2, tri for 3 and so on.
Therefore, the chemical name of compound 
is sulfur pentafluoride
Answer:
2.1x10⁹ years
Explanation:
U-238 is a radioactive substance, which decays in radioactive particles. It means that this substance will lose mass, and will form another compound, the Pb-206.
The time need for a compound loses half of its mass is called half-life, and knowing the initial mass (mi) and the final mass (m) the number of half-lives passed (n) can be found by:
m = mi/2ⁿ
The mass of Pb-206 will be the mass that was lost by U-238, so it will be mi - m. Thus, the mass ration can be expressed as:
(mi-m)/m = 0.337/1
mi - m = 0.337m
mi = 1.337m
Substituing mi in the expression of half-life:
m = 1.337m/2ⁿ
2ⁿ = 1.337m/m
2ⁿ = 1.337
ln(2ⁿ) = ln(1.337)
n*ln(2) = ln(1.337)
n = ln(1.337)/ln2
n = 0.4190
The time passed (t), or the age of the sample, is the half-life time multiplied by n:
t = 4.5x10⁹ * 0.4190
t = 1.88x10⁹ ≅ 2.1x10⁹ years
