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choli [55]
3 years ago
9

How many grams of sodium chloride are in 250mL of a 2.5M NaCI solution

Chemistry
1 answer:
Elden [556K]3 years ago
4 0
I think I did this right.

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Draw the Lewis structure, including unshared pairs, of the following molecules. Carbon has four bonds in the compound.
Galina-37 [17]

Explanation:

Refer to attachment.

  1. Propane
  2. Methanol (methyl alcohol)
  3. methyl fluoride
  4. ethyl fluoride

6 0
2 years ago
Since the electronegativity of O > C = H, the shared electrons in the covalent bonds of carbon dioxide (CO2) and methane (CH4
Stells [14]

Answer: option B. closer to oxygen in the case of CO2

Explanation:

5 0
3 years ago
Substance ΔG°f(kJ/mol) M3O4(s) −8.80 M(s) 0 O2(g) 0 Consider the decomposition of a metal oxide to its elements, where M represe
baherus [9]

Answer:

The equilibrium constant is  K =0.02867

The equilibrium pressure for oxygen gas is  P_{O_2} =  0.09367\  atm

Explanation:

  From the question we are told that

       The equation of the chemical reaction is

                    M_2 O_3 _{(s)} ----> 2M_{(s)} + \frac{3}{2} O_2_{(g)}

   The Gibbs free energy forM_3 O_4_{(s)} is  \Delta G^o_{1}  = -8.80 \ kJ/mol

  The Gibbs free energy forM{(s)} is  \Delta G^o_{2}  = 0 \ kJ/mol

    The Gibbs free energy forO_2{(s)} is  \Delta G^o_{3}  = 0 \ kJ/mol

The Gibbs free energy of the reaction is mathematically represented as

         \Delta G^o_{re} = \sum \Delta G^o _p - \sum G^o _r

         \Delta G^o_{re} = \sum \Delta G^o _1 - \sum( G^o _2 +G^o _3)

Substituting values

From the balanced equation

         \Delta G^o_{re} =[ (2 * 0) + (\frac{3}{2} * 0 )] - [1 * - 8.80]

        \Delta G^o_{re} = 8.80 kJ/mol =8800J/mol

The Gibbs free energy of the reaction can also be represented mathematically as

           \Delta G^o_{re} = -RTln K

Where R is the gas constant with a value of  R = 8.314 J/mol \cdot K

             T is the temperature with a given value  of  T = 298 K

             K is the equilibrium constant

Now equilibrium constant for a reaction that contain gas is usually expressed in term of the partial pressure of the reactant and products that a gaseous in state

The equilibrium constant for this chemical reaction  is mathematically represented as

                          K_p =[ P_{O_2}]^{\frac{3}{2} }

Where   [ P_{O_2}] is the equilibrium pressure of oxygen

         The p subscript shows that we are obtaining the equilibrium constant using the partial pressure of gas in the reaction

Now equilibrium constant the subject on the  second equation of the Gibbs free energy of the reaction

 

           K = e^{- \frac{\Delta G^o_{re}}{RT} }

Substituting values

           K= e^{\frac{8800}{8.314 * 298} }

            K =0.02867

Now substituting this into the equation above to obtain the equilibrium of oxygen

           0.02867 = [P_{O_2}]^{[\frac{3}{2} ]}

multiplying through by 1 ^{\frac{2}{3} }

        P_{O_2} =  [0.02867]^{\frac{2}{3} }

        P_{O_2} =  0.09367\  atm

       

3 0
3 years ago
What is the pH of a solution if the [H⁺] = 4.2 x 10⁻¹¹ M
liraira [26]

Answer:

10.4

Explanation:

-log(4.2x10^-11) = 10.37 = 10.4

3 0
2 years ago
2.524 g (5.1 × 106 g) ÷ (6.85 × 103 g) = ? How many significant figures should the result have?
irina1246 [14]
The correct answer is Three. Solving the given expression we get,

2.524 g (5.1 × 106 g) ÷ (6.85 × 103 g) = 1364.47÷ (6.85 × 103 g) = 1364.47÷ 705.55 = 1.93 
Here, the number of significant figures is three. Thus, the result should have three <span>significant figures.</span>
6 0
3 years ago
Read 2 more answers
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