Y=mx+c isn't an equation to solve. It's the slope-intercept formula for graphing lines.
y and x are the variables, and m and c are the constants.
As an example, the line y=4x+2 looks like this:
Answer:
k = –10
Step-by-step explanation:
From the question given above, the following data were obtained:
f(x) = x³ – 6x² – 11x + k
Factor => x + 2
Value of K =?
Next, we shall obtained the value of x from x + 2. This is illustrated below:
x + 2 = 0
Collect like terms
x = 0 – 2
x = –2
Finally, we shall determine the value of k as illustrated below:
f(x) = x³ – 6x² – 11x + k
x = –2
Thus,
f(–2) = 0
x³ – 6x² – 11x + k = 0
(–2)³ – (–2)² – 11(–2) + k = 0
–8 – (4) + 22 + K = 0
–8 – 4 + 22 + K = 0
10 + k = 0
Collect like terms
k = 0 – 10
k = –10
Thus, the value of k is –10
Answer:
70707mmm = 111nnn
Step-by-step explanation:
Using the basic equation of a line:
y = mx + c;. where m is slope and c is intercept on y axis.
Let mmm = y and nnn = x
(i) 333 = 212121m + c
(ii) 555 = 353535m + c
Making c the subject of the formula in both (i) and (ii)
c = 333 - 212121m = 555 - 353535m
353535m -212121m = 555 - 333
141414m = 222
m = 111/70707
Substitute in (i) above
c = 333 -333 = 0
Hence; y = 111/70707x + c
Finally, mmm = 111/70707 nnn
i.e. 70707mmm = 111nnn
Hope this helps.
Theoretical probability:
1 ... (16 and 2/3) %
2 ... (16 and 2/3) %
3 ... (16 and 2/3) %
4 ... (16 and 2/3) %
5 ... (16 and 2/3) %
6 ... (16 and 2/3) %
Experimental results:
1 ... 18
2 ... 16
3 ... 16
4 ... 17
5 ... 16
6 ... 17
The total number of rolls in the experiment was
(18 + 16 + 16 + 17 + 16 + 17) = 100
so the expected frequency for each outcome was 16-2/3 times,
and the SIMULATION probabilities were
1 ... 18%
2 ... 16%
3 ... 16%
4 ... 17%
5 ... 16%
6 ... 17%
To me, this looks fantastically close. The cube
could hardly be more fair than it actually is.
I think it might be 11x-8
I'm really sorry if that's wrong