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labwork [276]
3 years ago
11

Please someone answer and help :) ​

Chemistry
1 answer:
algol [13]3 years ago
7 0
13. D
14. A
15. C
16. B
17. F
18. E
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Methylamine is a weak base for which kb is 4.4*10 −4 . calculate the ph of a solution made by dissolving 0.070 mol of methylamin
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Answer is: pH of methylamine is 11.78.<span>

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Chemical reaction: CH₃NH₂(aq)+ H₂O(l) ⇌ CH₃NH₃⁺(aq) + OH⁻<span>(aq).
Kb(CH</span>₃NH₂) = 4,4·10⁻⁴.<span>
c</span>₀(CH₃NH₂) = n(CH₃NH₂) ÷ V(CH₃NH₂).

c₀(CH₃NH₂) = 0.070 mol ÷ 0.8 L = 0.0875 M.

c(CH₃NH₃⁺) = c(OH⁻) = x.

c(NH₂OH) = 0.0875 M - x; equilibrium concentration of methylamine.

Kb = c(CH₃NH₃⁺) · c(OH⁻) / c(CH₃NH₂).

0.00044 = x² /  (0.0875 M - x). 

Solve quadratic equation: x = c(OH⁻) = 0.00598 M.

pOH = -log(0.00598 M) = 2.22.

pH = 14 - 2.22 = 11.78.

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