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gizmo_the_mogwai [7]
4 years ago
6

When methane is burned with oxygen, the products are carbon dioxide and water. if you produce 9 grams of water and 11 grams of c

arbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction? 4 31 20 40 none of the above?
Chemistry
1 answer:
Alina [70]4 years ago
3 0
4 grams of methane is <span>burned with oxygen,.  Hope this helped</span>
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Draw the structure of 1,1-dimethylcyclohexane.
victus00 [196]
Cyclohexane - cyclic hydrocarbon with 6 carbon atoms.
2 methyl groups (-CH3) on carbon atom number 1

Hope it helped!

7 0
4 years ago
An avocado contains 234 Calories, with 21 grams of fat. Calculate the percent of Calories from fat.
tatyana61 [14]
36% of calories from fat
5 0
3 years ago
Calculate the pH and pOH of 500.0 mL of a phosphate solution that is 0.285 M HPO42– and 0.285 M PO43–. (Ka for HPO42- = 4.2x10-1
jekas [21]

Answer: when concentrations of acid and base are same, pH = pKa

PH = 12.38 pOH = 1.62

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8 0
3 years ago
An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having
dimulka [17.4K]

Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

Average atomic mass = 1.008 amu

Mass of first isotope = 1.007 amu

Mass of 2nd isotope = 2.014 amu

Most abundant isotope = ?

Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass  2.014 amu

1-x for isotopes having mass 1.007 amu

The average atomic mass is 1.008 amu

we will use the following equation,

2.014x + 1.007  (1-x) = 1.008  

2.014x + 1.007  - 1.007 x = 1.008  

2.014x - 1.007x  =  1.008  -  1.007

1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass  2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

0.9991 × 100= 99.91%

6 0
3 years ago
Choose the more reactive metal. K or Cu
mixas84 [53]
K is more reactive than Cu hope this helps!
3 0
3 years ago
Read 2 more answers
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