Answer:
0.1388 g
Explanation:
The mass of
obtained on precipitation = 236 mg
1 mg = 0.001 g
Thus, Mass of
= 0.236 g
Molar mass of
= 233.43 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of
= 0.001011 moles
According to the reaction,

Thus, moles of barium = 0.001011 moles
Molar mass of barium = 137.327 g/mol
Thus, Mass = Moles * Molar mass = 0.001011*137.327 g = 0.1388 g
Answer:
Theoretical yield of vanadium = 1.6 moles
Explanation:
Moles of
= 1.0 moles
Moles of
= 4.0 moles
According to the given reaction:-

1 mole of
react with 5 moles of 
Moles of Ca available = 4.0 moles
Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)
The formation of the product is governed by the limiting reagent. So,
5 moles of Ca on reaction forms 2 moles of V
1 mole of Ca on reaction for 2/5 mole of V
4.0 mole of Ca on reaction for
mole of V
Moles of V = 1.6 moles
<u>Theoretical yield of vanadium = 1.6 moles</u>
Alcohol is a pure substance
<span>c. Passing electric charge through the reactants Is the answer to you're question.
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