Which one of the following exhibits dipole-dipole attraction between molecules?
1 answer:
Answer: No one. All these molecules are nonpolar.
Explanation: Dipole-dipole attractions occur only between polar molecules. To know if a molecule is polar, you have to observe if their dipole moment (μ) is different from 0. You can do this by observing the vectors of charge in each molecule.
In all the molecules of the alternatives, the overall molecule is nonpolar (the sum of the vectors is equal to 0). So, these molecules are attracted only by induced dipole forces (weak forces that exist between nonpolar molecules).
For F2, this molecule is nonpolar because is composed of equal atoms. So, there isn't an atom which pulls the charge for itself.
You might be interested in
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle:
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
On an increase in the volume :
If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place.And equilibrium will shift in direction where number of gaseous moles are more.
On an decrease in the volume :
If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decease in pressure is taking place.And equilibrium will shift in direction where number of gaseous moles are less.
a.
On an increase in the volume :
As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to increase the amount of product we have to increase the pressure of the reactants molecules decrease the volume.
b.
As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to increase the amount of product we have to increase the pressure of the reactants molecules decrease the volume.
c.
As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to increase the amount of product we have to increase the pressure of the reactants molecules and decrease the volume .