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emmasim [6.3K]
3 years ago
11

Which one of the following exhibits dipole-dipole attraction between molecules?

Chemistry
1 answer:
Maslowich3 years ago
8 0

Answer: No one. All these molecules are nonpolar.

Explanation: Dipole-dipole attractions occur only between polar molecules.  To know if a molecule is polar, you have to observe if their dipole moment (μ) is different from 0. You can do this by observing the vectors of charge in each molecule.

In all the molecules of the alternatives, the overall molecule is nonpolar (the sum of the vectors is equal to 0). So, these molecules are attracted only by induced dipole forces (weak forces that exist between nonpolar molecules).

For F2, this molecule is nonpolar because is composed of equal atoms. So, there isn't an atom which pulls the charge for itself.

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A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate
AVprozaik [17]

Answer:

0.1388 g

Explanation:

The mass of BaSO_4 obtained on precipitation = 236 mg

1 mg = 0.001 g

Thus, Mass of BaSO_4 = 0.236 g

Molar mass of BaSO_4 = 233.43 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.236\ g}{233.43\ g/mol}

Moles of BaSO_4 = 0.001011 moles

According to the reaction,

Ba^{2+}+SO_4{2-}\rightarrow BaSO_4

Thus, moles of barium = 0.001011 moles

Molar mass of barium = 137.327 g/mol

Thus, Mass = Moles * Molar mass = 0.001011*137.327 g = 0.1388 g

4 0
4 years ago
What is a mineral used in making fertillizer <br>1. silver <br>2. silica <br>3. tin <br>4. gypsum​
Marat540 [252]

The Answer Is Gypsum

Hope That Helps!

5 0
4 years ago
Read 2 more answers
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 moles of
IRINA_888 [86]

Answer:

Theoretical yield of vanadium = 1.6 moles

Explanation:

Moles of V_2O_5 = 1.0 moles

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According to the given reaction:-

V_2O_5_{(s)} + 5Ca_{(l)}\rightarrow 2V_{(l)} + 5CaO_{(s)}

1 mole of V_2O_5 react with 5 moles of Ca

Moles of Ca available = 4.0 moles

Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)

The formation of the product is governed by the limiting reagent. So,

5 moles of Ca on reaction forms 2 moles of V

1 mole of Ca on reaction for 2/5 mole of V

4.0 mole of Ca on reaction for \frac{2}{5}\times 4 mole of V

Moles of V = 1.6 moles

<u>Theoretical yield of vanadium = 1.6 moles</u>

4 0
3 years ago
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Alcohol is a pure substance
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3 years ago
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<span>c. Passing electric charge through the reactants Is the answer to you're question.

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