All categories

3 years ago

What subatomic particle was discovered with the use of a cathode-ray tube

Chemistry

1 answer:

slamgirl [31]3 years ago

3 0

Answer:

The correct answer is: Electron

Explanation:

Electron (e⁻) is the negatively charged subatomic particle that has an electric charge of -1e (−1.6022 ×10⁻¹⁹ C). It was discovered by the English physicist, Sir Joseph John Thomson (J. J. Thomson) in the year 1897 by the cathode ray experiment.

In the cathode ray experiment, Sir Joseph John Thomson used the cathode ray tubes to conclude the presence of negatively charged small subatomic particle, known as electrons, in all atoms.

You might be interested in

What happens to the atoms and molecules in a substance as its temperature increases?

lana [24]

The molecules and atoms vibrate faster. As atoms vibrate faster the space between atoms also increases.

5 0

3 years ago

What is the correct formula for the compound formed between potassium and nitrogen?

LiRa [457]

K is in the first group can form ion K⁺,
N is in third group can form negative ion (8-5=3) N³⁻
$K^{+1}_{3}N^{3-},

K_{3}N 

is the answer

$

4 0

3 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

3 years ago

Read 2 more answers

What is the bond that forms between two ions and why does this bond form?

lidiya [134]

Ionic bonds form bc of a difference in charges; opposites attract, negative to positive

5 0

3 years ago

how to calculate the formula mass of H2S2, HFO2 an keep at least one decimal place in atomic masses from the periodic table

weqwewe [10]

H = 1.008
S = 32.066
F = 18.998
O = 15.999

(1.008 x 2) + (32.066 x 2) = 66.148 g/mol

(1.008) + (18.998) + (15.999 x 2) = 52.004

Let me know if you need any further help!

3 0

3 years ago