Answer:
The base is: ![3 \sqrt[3]{4}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B4%7D)
Step-by-step explanation:
Given
![f(x) = \frac{1}{4}(\sqrt[3]{108})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B108%7D%29%5Ex)
Required
The base
Expand 108
![f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B3%5E3%20%2A%204%7D%29%5Ex)
Rewrite the exponent as:
Expand
Rewrite as:
![f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%283%20%5Csqrt%5B3%5D%7B4%7D%29%5Ex)
An exponential function has the following form:
Where
By comparison:
![b =3 \sqrt[3]{4}](https://tex.z-dn.net/?f=b%20%3D3%20%5Csqrt%5B3%5D%7B4%7D)
So, the base is:
So 3+1=4 then you do the half you know 2 hlafs=whole so thats 1 and 4+1=5
5 is the answer
Answer:
Step-by-step explanation:
<u>Arc length formula:</u>
<u>Substitute values:</u>
- s = 2*3.14*15(80/360) = 20.93 in
Answer:
It has 1 term and a degree of 4.
Step-by-step explanation:
3j⁴k-2jk³+jk³-2j⁴k+jk³
= 3j⁴k-2j⁴k-2jk³+jk³+jk³
= j⁴k
So, in this expression, there is 1 term, and it has a degree of 4.
