Which group was fighting communists in Nicaragua in the 1980s?

A student has a mass of 90 kg what would his weight be on mars if the acceleration due to gravity is 3.7 ?

Mumz [18]

Answer:

333N

Explanation:

Once we have the object's mass, we can find the weight by multiplying it by the gravitational force, which it is subject to. Being that Mars has a gravitational force of 3.7m/s2, we multiply the object's mass by this quantity to calculate an object's weight on mars.

So an object or person on Mars would weigh 37.83% its weight on earth. Therefore, a person would be much lighter on mars. Conversely, a person is 62.17% heavier on earth than on Mars.

3 0

2 years ago

If a black hole is invisible how can we determine when one is present

Gelneren [198K]

Answer: you can’t

Explanation: i’m dumb too

8 0

2 years ago

Nitrogen increases volume during what physical change

atroni [7]

Effects of changes in volume in a reversible reaction in a chemical equilibrium can be predicted using Le Chatelier's Principle. I think this might be the answer, I hope it helps.

4 0

3 years ago

Consider the reaction, C2H4(g) + H2(g) - C2H6(8), where AH = -137 kJ. How many kilojoules are released when 3.5 mol of CH4

antiseptic1488 [7]

Answer: 480 kJ of energy is released when 3.5 mol of $C_2H_4$ reacts.

Explanation:

The balanced chemical reaction is:

$C_2H_4(g)+H_2(g)\rightarrow C_2H_6(g)$ $\Delta H=-137kJ$

Thus it is given that the reaction is exothermic (heat energy is released) as enthalpy change for the reaction is negative.

1 mole of $C_2H_4$ on reacting gives = 137 kJ of energy

Thus 3.5 moles of $C_2H_4$ on reacting gives = $\frac{137}{1}\times 3.5=480 kJ$ of energy

Thus 480 kJ of energy is released when 3.5 mol of $C_2H_4$ reacts.

7 0

2 years ago

Consider the following redox equation Mn(OH)2(s) + MnO4 –(aq)  MnO42 –(aq) (basic solution) When the equation is balanced with

inysia [295]

Answer : The balanced chemical equation is,

$2MnO_4^-(aq)+Mn(OH)_2(s)+4OH^-(aq)\rightarrow 3MnO_4^{2-}(aq)+2H_2O(l)$

The coefficient for $OH^-$ is, 4 and on reactant side of the equation $OH^-(aq)$ is present.

Explanation :

Rules for the balanced chemical equation in basic solution are :

First we have to write into the two half-reactions.
Now balance the main atoms in the reaction.
Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion $(OH^-)$ at that side where the less number of hydrogen are present.
Now balance the charge.

The half reactions in the basic solution are :

Reduction : $Mn(OH)_2(s)+1e^-\rightarrow MnO_4^{2-}(aq)$ ......(1)

Oxidation : $MnO_4^-(aq)+4OH^-(aq)\rightarrow MnO_4^{2-}(aq)+2H_2O(l)+2e^-$ .....(2)

Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$2MnO_4^-(aq)+Mn(OH)_2(s)+4OH^-(aq)\rightarrow 3MnO_4^{2-}(aq)+2H_2O(l)$

Thus, the coefficient for $OH^-$ is, 4 and on reactant side of the equation $OH^-(aq)$ is present.

6 0

2 years ago