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S_A_V [24]
3 years ago
5

Water and oxygen gas are the products of a chemical reaction.

Chemistry
2 answers:
Darina [25.2K]3 years ago
8 0
The answer is C.

H₂O₂ ----> H₂O + O₂
Jlenok [28]3 years ago
4 0

Answer:

C

Explanation:

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Nitrogen dioxide is one of the many oxides of nitrogen (often collectively called "NOx") that are of interest to atmospheric che
Helga [31]

Answer:

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

Explanation:

2NO_2(g)\rightleftharpoons N_2O_4(g)

Initially

3.0 atm                 0

At equilibrium

(3.0-2p)                 p

Equilibrium partial pressure of NO_2=2.1atm=3.0-2p

p = 0.45 atm

The value of equilibrium constant wil be given by :

K_p=\frac{p_{N_2O_4}}{(p_{NO_2})^2}=\frac{p}{(3.0-2p)^2}

K_p=\frac{0.45}{(2.1)^2}=0.10

After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :

2NO_2(g)\rightleftharpoons N_2O_4(g)

After adding 1.5 atm of NO_2:

(2.1+1.5) atm                0.45 atm

At second equilibrium:'

(3.6-2P)                     (0.45+P)

The expression of equilibrium can be written as:

K_p=\frac{p'_{N_2O_4}}{(p'_{NO_2})^2}

0.10=\frac{(0.45+P)}{(3.6-2P)^2}

Solving for P:

P = 0.37 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:

= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

5 0
3 years ago
Chelsi has talked to her artist friends about how much money they earn each year from working in the arts. She gathers these val
Citrus2011 [14]

Answer:

The median would be 6700

Explanation:

Arrange data values from lowest to highest value

The median is the data value in the middle of the set

.

Ordering a data set x1 ≤ x2 ≤ x3 ≤ ... ≤ xn from lowest to highest value, the median x˜ is the data point separating the upper half of the data values from the lower half.

If the size of the data set n is odd the median is the value at position p where

Formula for the median

p=n+12

x˜=xp

If n is even the median is the average of the values at positions p and p + 1 where

p=n2

x˜=xp+xp+12

If there are 2 data values in the middle the median is the mean of those 2 values.

7 0
3 years ago
Oxygen is a non-metal true or false
Sergio [31]

Answer:

This is true because oxygen belongs to the non-metal part of the periodic table.

4 0
4 years ago
Read 2 more answers
BRAINLIESTTTT ASAP!!! PLEASE HELP MEEEE :)
Scilla [17]

Precise is the close proximity of repeated measurements.  In order to be precise, you need two or more measurements.

Accurate is the close proximity to the real (or expected) measurement.

<u>For Example: </u>

You are at the grocery store buying watermelons.  The sign says that the watermelons all weigh 2 lbs.  You weigh 3 of them on the scale next to the watermelon display.  Their weights are 1.77, 1.80, and 1.82.  

→ The <u>scale is precise</u> because it weighs all 3 of them at nearly the same value.

→ The <u>scale is not accurate </u> because their weights are not close to the expected value of 2.0

You take one of the watermelons to the cashier.  The scale at the checkout counter weighs it as 1.99.  The scale at the checkout counter is accurate.  You cannot determine the precision of the scale at the checkout counter because you have no other values to compare it to.

Answer:  Precise CANNOT be determined by one measurement.  

               Accurate CAN be determined by one measurement.

4 0
4 years ago
Calculate the wavelength of the photon that would be absorbed or emitted. Round your answer to 3 significant digits.
Flauer [41]

This is an incomplete question, the image for the given question is attached below.

Answer : The wavelength of photon would be absorbed, 3.06\times 10^{-7}m

Explanation :

From the given diagram of energy we conclude that,

Energy at ground state, A = 400 zJ

Energy of 2nd excited state, C = 1050 zJ

Now we have to calculate the energy of the photon.

E=E_c-E_A

E=(1050-400)zJ= 650zJ=650\times 10^{-21}J

Now we have to calculate the wavelength of the photon.

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

E = energy of photon = 650\times 10^{-21}J

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength of photon  = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

650\times 10^{-21}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}

\lambda=3.06\times 10^{-7}m

Therefore, the wavelength of photon would be absorbed, 3.06\times 10^{-7}m

5 0
3 years ago
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