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Chemistry

1 answer:

telo118 [61]2 years ago

3 0

Answer: 11.25 moles of $O_2$ will be required to completely react with 2.25 moles of $C_3H_8$ .

Explanation:

The balanced chemical equation is:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

According to stoichiometry :

1 mole of $C_3H_8$ require = 5 moles of $O_2$

Thus 2.25 moles of $C_3H_8$ will require= $\frac{5}{1}\times 2.25=11.25moles$ of $O_2$

Thus 11.25 moles of $O_2$ will be required to completely react with 2.25 moles of $C_3H_8$ .

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