Question

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Answer 1

Answer: 11.25 moles of $O_2$ will be required to completely react with 2.25 moles of $C_3H_8$.

Explanation:

The balanced chemical equation is:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$  

According to stoichiometry :

1 mole of $C_3H_8$ require = 5 moles of $O_2$

Thus 2.25 moles of $C_3H_8$ will require=$\frac{5}{1}\times 2.25=11.25moles$  of $O_2$  

Thus 11.25 moles of $O_2$ will be required to completely react with 2.25 moles of $C_3H_8$.