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Romashka-Z-Leto [24]
3 years ago
6

What roles do cellular respiration and photosynthesis play in the carbon cycle?

Chemistry
1 answer:
I am Lyosha [343]3 years ago
8 0

Cellular respiration releases carbon dioxide into the environment while photosynthesis pulls carbon dioxide out of the atmosphere. c:

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Deuterium is a relatively uncommon form of hydrogen, but can be created from what common source?.
Elena-2011 [213]

Deuterium is a relatively uncommon form of hydrogen, but can be created from water.

  • Heavy hydrogen commonly  known as deuterium
  • stable isotopes of hydrogen
  • gets its name from the Greek word deuterons means second.
  • has only one proton and one neutron
  • nucleus of the hydrogen's deuterium atom is known as a deuteron containing one proton and one neutron.
  • Deuterium forms chemical bonds that are stronger than regular hydrogen
  • gas deuterium is colorless
  • Deuterated water is used in Magnetic Resonance Spectroscopy.
  • used in the determination of the isotopologue of various organic compounds.
  • used in Infrared Spectroscopy.

To know more about Deuterium visit : brainly.com/question/27870183

#SPJ4

8 0
2 years ago
The __________ system is made up of the nose, pharynx, trachea, lungs, bronchi, and alveoli. *
Reil [10]
Respiratory system is made of that
4 0
3 years ago
Read 2 more answers
In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq)+Sn2+(aq)→H2
allsm [11]

Answer:

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

Explanation:

SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)

Balancing in acidic medium:

First we will determine the oxidation and reduction reaction from the givne reaction :

Oxidation:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

Balance the charge by adding 2 electrons on product side:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)+2e^-....[1]

Reduction :

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)

Balance O by adding water on required side:

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

Now, balance H by adding H^+ on the required side:

SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

At last balance the charge by adding electrons on the side where positive charge is more:

SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)..[2]

Adding [1] and [2]:

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

4 0
3 years ago
can you help me with #7? #7 says "A substance enters into and is altered through the course of a chemical change. it is called a
Zigmanuir [339]
Reactant hope this helps
3 0
3 years ago
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Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.
vlada-n [284]

Answer:

2.03

Explanation:

Let's <u>assume we have 1 L of the solution</u>:

  • There would be 2.07 ethylene glycol moles.
  • The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can <u>calculate the molality</u>:

  • molality = moles of solute / kg of solvent
  • molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

3 0
2 years ago
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