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3 years ago

Based on patterns in the periodic table, which ion has a stable valence electron configuration?

1 answer:

4 0

The ions of Noble gases, group VIII elements have a full octet configuration on their outermost shell and as such are highly stable.

The periodic table is a systematic arrangement of elements in order of their atomic numbers into a set of 8 columns each called groups and a set of 7 rows each called a period.

Elements are arranged in different groups according to the number of Valence electrons they have.

For instance, elements in the group I of the periodic table are highly electropositive and as such are highly reactive.

The same is evident in group 7 elements are highly electronegative and have high electron affinity and as such are unstable and reactive.

However, Noble gases, group VIII elements have a full octet configuration on their outermost shell and as such are highly stable.

Consequently, the Noble gases ion has a stable Valence electron configuration.

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In the reaction FeCl2 + 2NaOH ->Fe(OH)2(s) + 2NaCl, if 6 moles of FeCl2 are added to 6 moles of Na0H, how many moles of NaOH

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Answer : The correct option is, (B) 6 mole

Explanation :

Given moles of $FeCl_2$ = 6 moles

Given moles of $NaOH$ = 6 moles

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$FeCl_2+2NaOH\rightarrow Fe(OH)_2+2NaCl$

From the given balanced reaction, we conclude that

As, 1 moles of $FeCl_2$ react with 2 moles of $NaOH$

So, 6 moles of $FeCl_2$ react with $\frac{2}{1}\times 6=12$ moles of $NaOH$

From this we conclude that, $FeCl_2$ is an excess reagent and $NaOH$ is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.

Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH

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In explanation.

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In the file attached is the answer, couldn´t answer it here.