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Alexxandr [17]
3 years ago
14

Which of the following can have their shares trade on the stock exchange​

Business
1 answer:
STALIN [3.7K]3 years ago
8 0

2+2=4-1=3 quick maths

Explanation:

;)

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| 50 POINTS | If The Oil Prices Around The World Rise , What Will Happen To The Oil Production In Texas?
timofeeve [1]
The oil will increase in texas
5 0
3 years ago
Read 2 more answers
Which is not true of birthday and/or annual review automatics?a. the purpose is to trigger a telephone call for a face-to-face m
Musya8 [376]

Answer: b. Quarterly automatic contacts decrease cross-sales and lead to reduced referrals

Explanation:

During the annual review of business considering automatics it is observed that there is always a decrease in cross sales and these leads to a reduce in referrals.

When these happens, clients who raise offer for referrals drop interest.

8 0
3 years ago
A consultant predicts that there is a 25 percent chance of earning $500,000 and a 75 percent chance of earning $100,000. The exp
antiseptic1488 [7]

Answer:

$173,205

Explanation:

According to the scenario, computation of the given data are as follows:

Given data:

Earning (X1) = $500,000

Chances of X1 (Y1) = 25%

Earning (X2) = $100,000

Chances of X2 (Y2) = 75%

Expected Profit (Z) = $200,000

Formula for solving the problem are as follows:

Standard deviation = [ (X1 - Z)^2 × Y1 + (X2 - Z)^2 × Y2 ]^1/2

By putting the value in the formula, we get

Standard deviation = [ ($500,000 - $200000)^2 × 0.25 + ($100,000 - $200,000)^2 × 0.75 ]^1/2

= [ $22,500,000,000 + $7,500,000,000 ]^1/2

= ($30,000,000,000)^1/2

= $173,205.08 or $173,205

Hence, $173,205 is the correct answer.

6 0
3 years ago
If the monthly income of the IBM employees follows a SYMMETRICAL NORMAL distribution, with a median of $5000 and a standard devi
AURORKA [14]

Answer:  mean monthly income = $5000

====================================================

Explanation

In any normal distribution, the median and mean are the same value.

-------------

The proof is as follows:

If mean > median was the case, then the distribution would be skewed to the right (ie positively skewed). The right tail is pulled longer than the left tail. But this would contradict the symmetrical nature of the normal distribution. So mean > median must not be the case.

If mean < median, then the distribution would be skewed to the left (negatively skewed). Visually this pulls the left tail longer than the right tail. Like in the previous paragraph, this contradicts the symmetrical nature of the normal distribution. So mean < median must not be the case.

Since mean > median cannot be true, and neither can mean < median, this must indicate mean = median.

-------------

So in short, any symmetrical distribution always has mean = median and they are at the very center of the distribution.

4 0
3 years ago
The labor-force participation rate is? a. 47.1 percent. b. 50.2 percent. c. 65.9 percent. d. 70.2 percent.
il63 [147K]

The labor-force participation rate is 70.2 percent
therefore the correct option is D

What is Labor force?
The labor force is made up of both employed people and unemployed people, and the unemployment rate is calculated by dividing the number of jobless people by the total labor force. If a person works for compensation or runs their own business for at least an hour any day of the week, including the twelfth of the month, they are regarded to be employed. If a person works for compensation or runs their own business for at least an hour any day of the week, including the twelfth of the month, they are regarded to be employed. In a family-run firm, individuals who put in at least fifteen hours of unpaid work are also regarded as employees. Employed people include those who are temporarily away from their work due to a vacation, illness, inclement weather, or other personal reasons. Those who worked full-time (35 hours or more during the survey week) and those who worked part-time are both considered to be in the employed category.

To learn more about Labor Force
brainly.com/question/24939447

#SPJ4

Complete Question
The labor-force participation rate is? a. 47.1 percent. b. 50.2 percent. c. 65.9 percent. d. 70.2 percent, e. none of the above

4 0
2 years ago
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