Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.
Im pretty sure it is 1/12 which if you need that as a fraction so it is unlikley.
Answer:
1. m= -2 1/3
2. m=35 (35 divided by -5 is -7 and -7+1 = -6)
3. m=-4 (2 times -4 is -8, 4+-8 equals -4)
Step-by-step explanation: