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Pani-rosa [81]
3 years ago
14

Change 200km/hr into m/sec​

Physics
2 answers:
Gekata [30.6K]3 years ago
8 0
55.556 mps is your answer!
Marysya12 [62]3 years ago
7 0

Answer:

200km/hr=55.55m/sec

Explanation:

200km/1hr×1000m/1km×1hr/3600sec=200,000/36000

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2. Sherlock Holmes established and ran the first ever crime laboratory.<br> True<br> False
alex41 [277]

Answer:

Explanation:

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3 0
3 years ago
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The shape of an atom.is <br><br> Spherical<br> Square<br> Pyramifal
zvonat [6]
Spherical because it’s more like clouds
7 0
3 years ago
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Near the surface of Earth an electric field points radially downward and has a magnitude of approximately 100 N/C. What charge (
pentagon [3]

Answer:

q=2.997\times 10^{-4}C

Sign-Negative

Explanation:

We are given that

Electric field =E=100NC^{-1} (Radially downward)

Acceleration=0.19 ms^{-2}(Upward)

Mass of charge=3 g=3\times 10^{-3}kg

1kg=1000g

We have to find the magnitude and sign of  charge would have to be placed on a penny .

By newton's second law

\sum F_y=ma

\sum F_y=qE-mg

Substitute the values then we get

qE-mg=ma

Substitute the values then we get

q(100)-3\times 10^{-3}(9.8)=3\times 10^{-3}(0.19)

100q-29.4\times 10^{-3}=0.57\times 10^{-3}

100q=0.57\times 10^{-3}+29.4\times 10^{-3}=29.97\times 10^{-3}

q=\frac{29.97\times 10^{-3}}{100}

q=2.997\times 10^{-4}C

Sign of charge =Negative

Because electric force acting  in opposite direction of electric field therefore,charge on penny will be negative.

4 0
4 years ago
Ill give Brainliest to who ever answers first
forsale [732]

Answer:

Is there a question?

Explanation:

5 0
3 years ago
This is the change in kinetic energy of a system in which a 16 kg object moving at 25 m/s slows to a velocity of 20 m/s
Dennis_Churaev [7]

The kinetic energy of an object is given by

KE = 0.5mv²

where m is the mass and v is the velocity.

To calculate the change in kinetic energy...

Initial KE:

KEi = 0.5mVi²

where Vi is the initial velocity.

Final KE:

KEf = 0.5mVf²

where Vf is the final velocity.

ΔKE = KEf - KEi

ΔKE = 0.5mVi² - 0.5mVf²

ΔKE = 0.5m(Vf²-Vi²)

Given values:

m = 16kg

Vi = 25m/s

Vf = 20m/s

Plug in the given values and solve for ΔKE:

ΔKE = 0.5×16×(20²-25²)

ΔKE = -1800J

5 0
3 years ago
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