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3 years ago

The shape of an atom.is Spherical Square Pyramifal

Physics

2 answers:

zvonat [6]3 years ago

7 0

Spherical because it’s more like clouds

iVinArrow [24]3 years ago

4 0

The shape of an atom is spherical

Answer: spherical

<u>Explanation: </u>

In 1911, Rutherford proved with his experiment that the spread of positive, and negative particle inside the atom wasn't uniform. It was assumed to be uniform according to the atomic model given in 1904 by J.J. Thomson.

According to the latest atomic model, the atom has a dense nucleus made of neutrons and protons in the rest state whereas; the electrons revolve around the atomic nucleus in its respective orbital orientations.

The shape of an atom depends upon the electron's angular momentum and the electrostatic force between the atomic particles. Since the atoms don't have well defined spherical boundaries because of various orbital orientations around the nucleus, their shape cannot be stated as spherical.

However, only simple atoms exhibit spherical shape and not the complex ones.

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Guys please help me

Likurg_2 [28]

Answer:

1) $t=2.26\: s$

2) $S=33.9\: m$

3) $v=26.77\: m/s$

4) $\alpha=55.92$

Explanation:

We can use the following equation:

$y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}$

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.

$0=25-0.5*9.81*t^{2}$

$t=2.26\: s$

The equation of the motion in the x-direction is:

$v_{ix}=\frac{S}{t}$

$15=\frac{S}{2.26}$

$S=33.9\: m$

The velocity in the y-direction of the stone will be:

$v_{fy}=v_{iy}-gt$

$v_{fy}=0-(9.81*2.26)$

$v_{fy}=-22.17\: m/s$

Now, the velocity in the x-direction is 15 m/s then the velocity will be:

$v=\sqrt{v_{x}^{2}+v_{fy}^{2}}=\sqrt{15^{2}+(-22.17)^{2}}$

$v=26.77\: m/s$

The angle of this velocity is:

$tan(\alpha)=\frac{22.17}{15}$

$\alpha=tan^{-1}(\frac{22.17}{15})$

$\alpha=55.92$

Then α=55.92° negative from the x-direction.

I hope it helps you!

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