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xenn [34]
2 years ago
14

1 second What is the frequency of this wave? O 1 02 O 3 O4

Physics
1 answer:
ankoles [38]2 years ago
6 0

Answer:

Option (1) f = 1

Explanation:

Formula for Frequency (F) = 1/t where t = Time in seconds.

F = 1/1

F = 1 hz ( hz or hertz is the unit for Frequency ).

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Find the net force of the box and the acceleration. 10 points. Will give brainliest.
zysi [14]

Answer:

38.6 N

2.57 m/s²

Explanation:

Draw a free body diagram of the box.  There are four forces:

Weight force mg pulling down,

Normal force N pushing up,

Friction force Nμ pushing left,

and applied force P pulling at an angle 40°.

Sum of forces in the y direction:

∑F = ma

N + P sin 40° − mg = 0

N = mg − P sin 40°

The net force in the x direction is:

∑F = P cos 40° − Nμ

∑F = P cos 40° − (mg − P sin 40°) μ

∑F = P cos 40° − mgμ + Pμ sin 40°

∑F = P (cos 40° + μ sin 40°) − mgμ

Plugging in values:

∑F = (80 N) (cos 40° + 0.23 sin 40°) − (15 kg) (10 m/s²) (0.23)

∑F = 38.6 N

Net force equals mass times acceleration:

∑F = ma

38.6 N = (15 kg) a

a = 2.57 m/s²

4 0
3 years ago
Explain the working and principle of perisocope.​
aksik [14]

Answer:

a periscope use total internal reflection to allow us to see things

the reflection happens at 45°

Explanation:

6 0
3 years ago
Easy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loo
kumpel [21]

Answer:

v = 17.30 m / s

Explanation:

For this exercise we will use Newton's second law

at the bottom of the loop and stopped

           ∑ F = 0

           N-W = 0

           N = W

            W = 770 N

the mass of the body is

            W = mg

             m = W / g

            m = 770 / 9.8

            m = 78.6 kg

on top of the loop and moving

           ∑ F = m a

           N + W = m a

note that the three vectors go in the same vertical direction down

           

the centripetal acceleration is

           a = v² / r

we substitute

           N + W = m v² / r

           v = \sqrt{(N+W) \frac{r}{m} }

let's calculate

          v = \sqrt{ (350+770) \frac{21}{78.6} }

          v = 17.30 m / s

7 0
3 years ago
It took 3 seconds for an object that was thrown up with velocity vo from
otez555 [7]

Answer:

ik u got it bc this was 2 weeks ago

Explanation:

but yes and yuea

5 0
3 years ago
A fat person weighing 80 Kg falls on a concrete floor from 2m. If whole of the mechanical energy is converted into heat energy,
sasho [114]

Answer:

The heat produced is 1568 J

Explanation:

The given parameters are;

The mass of the person, m = 80 kg

The height from which the person falls, h = 2 m

Mechanical Energy, ME = Potential Energy, PE + Kinetic Energy, KE

At the height, from where the person falls, the initial velocity of the person = 0 m/s

Therefore;

The initial kinetic energy, K.E. = 1/2·m·v² = 1/2 × 80 kg × (0 m/s)² = 0 J

From which we have;

The Mechanical Energy, M.E. = The initial Potential Energy, P.E. + 0 J

∴ The Mechanical Energy, M.E. = The initial Potential Energy, P.E.

The initial Potential Energy, P.E. = m·g·h

Where;

m = The mass of the person

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ The initial Potential Energy, P.E. = 80 kg × 9.8 m/s² × 2 m = 1568 J

The Mechanical Energy, M.E. = The initial Potential Energy, P.E. = 1568 J

The whole mechanical energy is converted into heat energy, therefore, we have;

The Mechanical Energy, M.E. = The heat energy = 1568 J

The heat produced = The heat energy = 1568 J.

4 0
2 years ago
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