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Degger [83]
3 years ago
5

Nitrogen dioxide decomposes to nitric oxide and oxygen via the reaction: 2NO2 → 2NO + O2 In a particular experiment at 300 °C, [

NO 2 ] drops from 0.0100 to 0.00650 M in 100 s. The rate of disappearance of NO2 for this period is __________ M/s.
Chemistry
1 answer:
serious [3.7K]3 years ago
6 0

Answer: The rate of disappearance of NO_2 is 3.5\times 10^{-5}M/s

Explanation:

The given chemical reaction is:

2NO_2\rightarrow 2NO+O_2

The rate of the reaction for disappearance of NO_2 is given as:

\text{Rate of disappearance of }NO_2=-\frac{\Delta [NO_2]}{\Delta t}

Or,

\text{Rate of disappearance of }NO_2=-\frac{C_2-C_1}{t_2-t_1}

where,

C_2 = final concentration of NO_2 = 0.00650 M

C_1 = initial concentration of NO_2 = 0.0100 M

t_2 = final time = 100 minutes

t_1 = initial time = 0 minutes

Putting values in above equation, we get:

\text{Rate of disappearance of }NO_2=-\frac{0.00650-0.0100}{100-0}\\\\\text{Rate of disappearance of }NO_2=3.5\times 10^{-5}M/s

Hence, the rate of disappearance of NO_2 is 3.5\times 10^{-5}M/s

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What is the pH of a substance that has a hydrogen ion concentration of<br> 8.8x10^(-5) M? *
stealth61 [152]

Answer:

The pH of the substance is 4,06.

Explanation:

The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and greater than 7 to 14 basic. It is calculated as:

pH = -log (H +)

pH= -log (8.8x10^-5)

<em>pH=4,06</em>

5 0
3 years ago
What is the heat of fusion of water in calories per mole?​
Mumz [18]

Answer:

<u><em>79.72 Calories</em></u>

Explanation:

6 0
2 years ago
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How do you figure out molality
hodyreva [135]
*The molality of a solution is calculated by taking the moles of solute and dividing by
the kilograms of solvent* Basically if we had 1.00 mole of sucrose (it's about 342 3 grams) and
proceeded to mix it into exactly 1.00 liter water. It would dissolve and make sugar
water. We keep adding water, dissolving and stirring until all the solid was gone. We
then made sure everything was well-mixed.
What would be the molality of this solution? Notice that my one liter of water weighs
1000 grams (density of water = 1.00 g / mL and 1000 mL of water in a liter).
3 0
2 years ago
State the oxidation number of S in <br><img src="https://tex.z-dn.net/?f=H_%7B2%7DSO_%7B3%7D" id="TexFormula1" title="H_{2}SO_{3
Nezavi [6.7K]

Taking into account the definition of oxidation number, the oxidation numbers of S in H₂SO₃ is 4.

<h3>Definition of oxidation number</h3>

The oxidation number is the charge that an atom has; is an integer that represents the number of electrons an atom puts into play when it forms a given compound.

In other words, the oxidation number of an element is a value that indicates the number of electrons that element gains or loses when it combines with another.

<h3>Oxidation number determination</h3>

To determine the oxidation state of different elements it is necessary to know that:

  • The oxidation number of hydrogen in a compound is +1, except in metal hydrides, where is –1.
  • The oxidation number of oxygen in a compound is –2, except in peroxides, where it is –1.

On the other side, the sum of the oxidation numbers of the existing elements in a chemical formula must add up to zero.

Then, considering the oxidation numbers of each element, multiplying it by the number of existing elements in the chemical formula and adding it and equaling it to zero, the value of the missing oxidation number can be obtained.

<h3>Oxidation numbers of S</h3>

In this case, the oxidation numbers of S in H₂SO₃ is calculated as:

2× (+1) + oxidation numbers of S + 3×(-2)= 0

2 + oxidation numbers of S -6= 0

oxidation numbers of S -4= 0

<u><em>oxidation numbers of S= 4</em></u>

Finally, the oxidation numbers of S in H₂SO₃ is 4.

Learn more about the oxidation number:

brainly.com/question/8990767

brainly.com/question/6498977

5 0
2 years ago
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Copper has a density of 8.96 g/cm3. If 75.0 g of copper is added to 50.0 mL of water in a graduated cylinder, to what volume rea
Tcecarenko [31]

Answer:

The answer to your question is    Final volume = 58.37 ml

Explanation:

Data

density = 8.96 g/cm³

mass = 75 g

volume of water = 50 ml

Process

1.- Calculate the volume of copper

  Density = mass / volume

Solve for volume

  Volume = mass / density

Substitution

  Volume = 75/8.96

Simplification

  Volume = 8.37cm³    or 8.37 cm³

2.- Calculate the new volume of water in the graduated cylinder

  Final volume = 50 + 8.37

  Final volume = 58.37 ml

3 0
3 years ago
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