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3 years ago

2 Na + Cl2 --> 2 NaCl

Chemistry

1 answer:

Rzqust [24]3 years ago

4 0

Answer:

12.208 L

Explanation:

We'll begin by calculating the number of mole in 25 g of Na. This can be obtained as follow:

Mass of Na = 25 g

Molar mass of Na = 23 g/mol

Mole of Na =?

Mole = mass /Molar mass

Mole of Na = 25/23

Mole of Na = 1.09 moles

Next, we shall determine the number of mole of Cl2 required to react with 1.09 moles of Na. This can be obtained as follow:

2Na + Cl2 –> 2NaCl

From the balanced equation above,

2 moles of Na reacted with 1 mole of Cl2.

Therefore, 1.09 moles of Na will react with = (1.09 × 1)/2 = 0.545 mole of Cl2.

Thus, 0.545 mole of Cl2 is needed for the reaction.

Finally, we shall determine the volume of Cl2 required for the react as follow:

Recall: 1 mole of any gas occupy 22.4 L at STP.

1 mole of Cl2 occupied 22.4 L at STP.

Therefore, 0.545 mole of Cl2 of Cl2 will occupy = 0.545 × 22.4 = 12.208 L at STP.

Therefore, 12.208 L of Cl2 is needed for the reaction.

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1 year ago

PLEASE HELP!

Tanzania [10]

Molar mass:

KCl = 74.55 g/mol

KClO3 = 122. 55 g/mol

Calculation of the mass of KClO3 :

2 KClO3 = 2 KCl + 3 O2

2* 122.55 g KClO3 ------------------ 2 * 74.55 g KCl
mass KClO3 ?? --------------------- 25.6 g KCl

mass KClO3 = 25.6 * 2 * 122.55 / 2 * 74.55

mass KClO3 = 6274.56 / 149.1

mass = 42.082 g of KClO3

Therefore:

1 mole KClO3 ---------------------- 122.55 g
?? moles KClO3 ------------------- 42.082 g

moles KClO3 = 42.082 * 1 / 122.55

moles KClO3 = 42.082 / 122.55

=> 0.343 moles of KClO3

Answer C

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3 years ago

Dehydration of 2-methyl-2-pentanol forms one major and one minor organic product. Draw the structures of the two organic product

Korvikt [17]

Answer:

The major product is 2-methyl-2-pentene [ CH₃-CH₂-CH=C(CH₃)₂ ] and a minor product 2-methyl-1-pentene [ CH₃-CH₂-CH₂-C(CH₃)=CH₂ ].

Explanation:

Dehydration reaction is a reaction in which a molecule loses a water molecule in the presence of a dehydrating agent like sulfuric acid (H₂SO₄).

Dehydration reaction of 2-methyl-2-pentanol gives a major product 2-methyl-2-pentene and a minor product 2-methyl-1-pentene.

CH₃-CH₂-CH₂-C(CH₃)₂-OH (2-methyl-2-pentanol)→ CH₃-CH₂-CH=C(CH₃)₂ (2-methyl-2-pentene, major) + CH₃-CH₂-CH₂-C(CH₃)=CH₂ (2-methyl-1-pentene, minor)

Since more substituted alkene is more stable than the less substituted alkene. So, the trisubstituted alkene, 2-methyl-2-pentene is more stable than the disubstituted alkene, 2-methyl-1-pentene.

Therefore, the trisubstituted alkene, 2-methyl-2-pentene is the major product and the disubstituted alkene, 2-methyl-1-pentene is the minor product.

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3 years ago

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Answer:

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Explanation:

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3 years ago

A student mixes a 10.0 ml sample of 1.0 m naoh(aq) with a 10.0 ml sample of 1.0 m hcl(aq) in a polystyrene container. the temper

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Hrxn = Q reaction / mol of reaction
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3 years ago