Answer:
It is not. A multiplicative inverse is the reciprocal for a number. For a fraction, the form would change from a/b to b/a. In this case the multiplicative inverse of 7/8 would be 8/7.
The radius is half the diameter. Divide the diameter by 2 to find the radius.
Radius = 2 meters / 2 = 1 meter.
You need to include the image of the question it doesn’t make sense if
What are the next three terms in the sequence 2, -4, 8, -16, 32, ...? A. -128, 256, -512 B. 160, 320, 640 C. 160, -320, 640 D. -
miv72 [106K]
Common ratio is -2
next 3 terms :
32 * -2 = -64
-64 * -2 = 128
128 * -2 = -256
answer is D
The solution set is
![c \geq 5](https://tex.z-dn.net/?f=c%20%5Cgeq%205)
, meaning that all
![c](https://tex.z-dn.net/?f=c)
at least
![5](https://tex.z-dn.net/?f=5)
satisfy this constraint.
If
![c=5](https://tex.z-dn.net/?f=c%3D5)
, we have
![x < 5](https://tex.z-dn.net/?f=x%20%3C%205)
and
![x > 5](https://tex.z-dn.net/?f=x%20%3E%205)
, meaning
![x](https://tex.z-dn.net/?f=x)
has to be both greater than and less than
![5](https://tex.z-dn.net/?f=5)
, which is impossible. If
![c](https://tex.z-dn.net/?f=c)
is any greater,
![x > c > 5](https://tex.z-dn.net/?f=x%20%3E%20c%20%3E%205)
, so
![x](https://tex.z-dn.net/?f=x)
still must be greater and less than
![5](https://tex.z-dn.net/?f=5)
at the same time. So for all
![c \geq 5](https://tex.z-dn.net/?f=c%20%5Cgeq%205)
, the system
![x < 5, x > c](https://tex.z-dn.net/?f=x%20%3C%205%2C%20x%20%3E%20c)
has no solution.