All categories

3 years ago

¿Cuál es la energía potencial de un objeto que tiene una masa de 12kg y se encuentra en un anaquel a una altura de 7m?

Physics

1 answer:

Novosadov [1.4K]3 years ago

5 0

1) 84
2) 120
I’m not sure so if this is wrong I’m sorry

You might be interested in

Mr. Garcia uses magnets to hold a poster on a steel filing cabinet because a main component of steel is _____.

KonstantinChe [14]

The main component of steel is iron ... the mother of all magnetic material.

8 0

4 years ago

Read 2 more answers

What decibel reading corresponds to a pressure amplitude of 0.2 W/m^2?

horsena [70]

I = pressure amplitude given = 0.2 W/m²

dB = decibel reading

decibel reading from the pressure amplitude is given as

dB = 10 log₁₀ (I/10⁻¹²)

inserting the values in the above equation

dB = 10 log₁₀ (0.2/10⁻¹²)

dB = 10 log₁₀ (2 x 10⁻¹/10⁻¹²)

dB = 10 log₁₀ (2 x 10⁻¹.10¹²)

dB = 10 log₁₀ (2 x 10¹²⁻¹)

dB = 10 log₁₀ (2 x 10¹¹)

dB = 113.01 db

hence the decibel reading comes out to be 113.01 db

4 0

3 years ago

There is a simple relationship between the energy for a photon of light Ephoton in units of eV (electron volts) and its waveleng

Eva8 [605]

Answer:

$\lambda=620\ nm$

$E_p=1.9682\ eV$

$E_p=206.67\ eV$ is the photon energy of an x-ray

Explanation:

Given:

Energy of photon, $E_p=2\ eV$

Then according to given:

$E_p=\frac{1240}{\lambda}$

$2=\frac{1240}{\lambda}$

$\lambda=620\ nm$ is the wavelength

Again,

Energy of photon, $E_p=?$

wavelength of the light, $\lambda=630\ nm$

$E_p=\frac{1240}{630}$

$E_p=1.9682\ eV$

<u>Now, photon energy for an x-ray:</u>

wavelength, $\lambda=6\ nm$

$E_p=\frac{1240}{6}$

$E_p=206.67\ eV$ is the photon energy of an x-ray

3 0

3 years ago

The Kinetic energy, K, of an object with mass m moving with velocity v can be found using the formula - E_{\text{k}}={\tfrac {1}

tester [92]

Answer:

The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.

Explanation:

Kinetic energy is defined as energy possessed by an object due to its motion.It is calculated by:

$K.E=\frac{1}{2}mv^2$

Kinetic energy of the 5 kg object.

Mass of object,m = 5 kg

Velocity of an object = v

$K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 5kg\times v^2$

Kinetic energy of the 20 kg object.

Mass of object,m' = 20 kg

Velocity of an object = v'

$K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 20kg\times v'^2$

The ratio of the kinetic energy of the 5 kilogram object to the kinetic energy of the 20-kilogram object:

$\frac{K.E}{K.E'}=\frac{\frac{1}{2}\times 5kg\times v^2}{\frac{1}{2}\times 20kg\times v'^2}$

Given that, v = 2v'

$\frac{K.E}{K.E'}=\frac{1}{1}$

The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.

3 0

3 years ago

Can someone help me

Illusion [34]

Thomas Edison is the answer im 100% sure of it.

5 0

3 years ago