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Lubov Fominskaja [6]

2 years ago

8

In what way do sound waves differ from radio waves?.

1 answer:

Akimi4 [234]2 years ago

4 0

Radio waves are a type of electromagnetic wave that can travel when there is no medium, whereas sound waves are a type of mechanical wave that cannot travel if there is no medium

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A thermos bottle has two layers, a glass layer and a vacuum layer. The vacuum layer is the better _____.

BigorU [14]

The vacuum layer is the better insulator.
A thermos bottle like this has two walls made of glass and vacuum layer between those walls. Vacuum layer has very few molecules and they are distant from each other so heat transfer is prevented. That way liquid in thermos remain warm or cold.

6 0

3 years ago

A train is uniformly accelerated and passes

cupoosta [38]

Answer:

Explanation:

18 km/hr(1000 m/km) / (3600 s/hr) = 5 m/s

36 km/hr = 10 m/s

v² = u² + 2as

a = (v² - u²)/2s

a = (10² - 5²)/2(1000) = 0.0375 m/s²

v² = 10² + 2(0.0375)(1000)

v² = 175

v = 13.22875... ≈ 13 m/s ≈ 48 km/hr

v = u + at

t = (v - u) / a

t = (10 - 5)/0.0375 = 133.333... 133 s

t = (13.22875 - 10) / 0.0375 = 86.1 s

6 0

3 years ago

A soccer ball kicked with a force of 12.5 N accelerates at 6.2 m/s’ to the right. What is the mass of the ball? Answer in units

stepladder [879]

Answer:

m = 2.01[kg]

Explanation:

This problem can be solved using Newton's second law which tells us that the force applied on a body is equal to the product of mass by acceleration.

$F =m*a$

where:

F = force = 12.5 [N]

m = mass [kg]

a = acceleration = 6.2 [m/s²]

$12.5=m*6.2\\m = 2.01[kg]$

3 0

3 years ago

PLEASE HELP!!!!!

svet-max [94.6K]

gytaicdugocgvulaywlhjcblasdhbcbaulshcdhchuvascvlhsdlvas

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4 0

3 years ago

Read 2 more answers

Two projectile launchers are beside one another on level ground. Both launchers are directed at the same angle with respect to g

kakasveta [241]

Answer:

(a) Projectile B will travel 4 times as far as projectile A prior to landing

Explanation:

Initial velocity = v

Angle at which the projectile is shot at = θ

g = Acceleration due to gravity

Range of a projectile is given by

$R=\frac {v^{2}\sin 2\theta}{g}$

When Initial velocity = v

$R_A=\frac{v^{2}\sin 2\theta}{g}$

When Initial velocity = 2v

$R_B=\frac{(2v)^{2}\sin 2\theta}{g}\\\Rightarrow R_B=\frac{4v^2\sin 2\theta}{g}$

Dividing the equtions, we get

$\frac{R_A}{R_B}=\frac{\frac{v^{2}\sin 2\theta}{g}}{\frac{4v^2\sin 2\theta}{g}}$

Here, the angle at which the projectiles are fired at are equal.

$\frac{R_A}{R_B}=\frac{1}{4}\\\Rightarrow R_B=4R_A$

Hence, projectile B will travel 4 times as far as projectile A prior to landing

7 0

3 years ago