Ask question

Ask question

All categories

3 years ago

8

Cody lives in Florida along the eastern coast. The kind of air mass likely to occur

1 answer:

Svetllana [295]3 years ago

5 0

The air is likely to be humid because it is coastal and very warm there

You might be interested in

Determine the work done by 2. 00 kg of water when it is all boiled to steam at 100 ∘c. Assume a constant pressure of 1. 00 atm.

neonofarm [45]

The work done by the water at the constant pressure is $-4.52 \times 10^6 \ J$ .

<h3>Heat required to boil the water</h3>

The heat required to boil the water is calculated as follows;

$Q = mL_v\\\\$

where;

$L_v$ is the heat of vaporization of water = 22.6 x 10⁵ J/kg
m is mass of water

$Q = 2 \times 22.6 \times 10^5\\\\Q = 4.52 \times 10^6 \ J$

<h3>Work done by the water</h3>

The work done by the water at the constant pressure is equal to the heat gained by the water.

$W = - \Delta H\\\\W = -4.52 \times 10^6 \ J$ .

Learn more about first law of thermodynamics here: brainly.com/question/2965070

4 0

3 years ago

Sound can travel through a medium, but it does not require a medium. <br> a. True<br> b. False

pishuonlain [190]

The statement is false. Sound REQUIRES a material medium
in order to propagate from one place to another..

6 0

4 years ago

How does an executive order differ from a statue?

ICE Princess25 [194]

Answer: Executive Order on Protecting American Monuments, Memorials, and Statues against our country are public monuments, memorials, and statues.

Explanation: learned it last week

6 0

3 years ago

What would most likely happen if one of the runners bagan jogging in knee-deep water

Nesterboy [21]

Then they will most likely slow down unless they do high knees or something like that

7 0

4 years ago

A 60 W light bulb has a resistance of 880 Ω

Andreas93 [3]

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf{• \: Power \: (P) = 60 \: w}$

$\sf{• \: Resistance \: (R) = 880 \: Ω}$

$\\$

<h2> $\bf{ \underline{To \: Find :- }}$ </h2>

$\sf• \: The \: Current \: (I).$

$\\$

$\huge\bf{ \underline{ Solution :- }}$

$\sf We \: know \: that,$

$\bf \red {\bigstar{ \: P = I^{2} R}}$

$\rightarrow \sf 60 = I^{2} \times 880$

$\rightarrow \sf \frac{60}{880} = I^{2}$

$\rightarrow \sf I^{2} = 0.0681$

$\rightarrow \sf I = \sqrt{0.0681}$

$\rightarrow \sf I = 0.261 \: \: (approx.)$

$\\$

$\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)$

7 0

3 years ago