2 x 6,000=x(variable)
Solve
Answer:
f(-3)=5x^2+5x*3
-f*3=5x^2+5*3x
-3f=5x^2+15x
f=-5x(x+3)/3
f(-9)=5x^2+5x*3
-f*9=5x^2+5*3x
-9f=5x^2+15x
f=-5x(x+3)/9
Step-by-step explanation:
hope it helps you?
Let h represent the height of the building. Then the difference between the two angle measurement locations is
.. h/tan(39°) -h/tan(50°) = 300 ft
.. h = (300 ft)/(1/tan(39°) -1/tan(50°))
.. h ≈ 758 ft
The height of the building is about 758 feet.
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