If the other sweets are chocolates then 4 in every 5 sweets are chocolates so 4/5
Answer:14708
Step-by-step explanation:Exponential Functions:
y=abxy=ab^x this is not right not correct
y=ab
x
a=starting value = 13000a=\text{starting value = }13000
a=starting value = 13000
r=rate = 2.5%=0.025r=\text{rate = }2.5\% = 0.025
r=rate = 2.5%=0.025
Exponential Growth:\text{Exponential Growth:}
Exponential Growth:
b=1+r=1+0.025=1.025b=1+r=1+0.025=1.025
b=1+r=1+0.025=1.025
Write Exponential Function:
y=13000(1.025)xy=13000(1.025)^x
y=13000(1.025)
x
Put it all together
Plug in time for x:\text{Plug in time for x:}
Plug in time for x:
y=13000(1.025)5y=13000(1.025)^{5}
y=13000(1.025)
5
y=14708.30677y= 14708.30677
y=14708.30677
Evaluate
y≈14708y\approx 14708
y≈14708
Answer:
4
explanation:
well 18 minus 12 would equal 6. correct? so we would add x to 6 so the new equation would be 6 + x = 10 or to make it easier just do 10 - x = 6
Answer:
The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.
Step-by-step explanation:
Assumptions:
1. The sampling from the different discussion sections was independent and random.
2. The populations are normal with means and constant variance
There's no variation among the discussion sections
There's variation among the discussion sections
Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87 0.99986
Residuals 189 7584.11 40.13
Test Statistic = 
Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.
Answer:yes
Step-by-step explanation:
