Is it 22m...look at the other side shouldn't it be the same (sorry if I didn't help :))))))))
Answer:
![x=38.5^\circ](https://tex.z-dn.net/?f=x%3D38.5%5E%5Ccirc)
Step-by-step explanation:
Given that the left angle = ![(3x-3)^\circ](https://tex.z-dn.net/?f=%283x-3%29%5E%5Ccirc)
The right angle across from it ![= 6(x-10)^\circ](https://tex.z-dn.net/?f=%3D%206%28x-10%29%5E%5Ccirc)
The other two angles are x and x.
We know that the sum of angles at a point equals 360 degrees.
Therefore,
![(3x-3)^\circ+6(x-10)^\circ+x+x=360^\circ\\3x-3+6x-60+2x=360\\11x-63=360\\11x=360+63\\11x=423\\x=38.5^\circ](https://tex.z-dn.net/?f=%283x-3%29%5E%5Ccirc%2B6%28x-10%29%5E%5Ccirc%2Bx%2Bx%3D360%5E%5Ccirc%5C%5C3x-3%2B6x-60%2B2x%3D360%5C%5C11x-63%3D360%5C%5C11x%3D360%2B63%5C%5C11x%3D423%5C%5Cx%3D38.5%5E%5Ccirc)
The value of x is approximately 38.5 degrees.
Answer:
17.5
Step-by-step explanation:
11 + 24 = 35 /2
Answer:
h = 57.73 m
Step-by-step explanation:
We have,
The angle of elevation of the top of tower to be 30 degree
James is 100 m away horizontally from the base of the tower.
It is required to find the height of the tower.
Here, angle is 30 degree
Base, b = 100 m
Let h is the height of the tower. The relation between base and height is given by :
![\tan\theta=\dfrac{h}{b}\\\\h=b\times \tan\theta\\\\h=100\times \tan(30)\\\\h=57.73\ m](https://tex.z-dn.net/?f=%5Ctan%5Ctheta%3D%5Cdfrac%7Bh%7D%7Bb%7D%5C%5C%5C%5Ch%3Db%5Ctimes%20%5Ctan%5Ctheta%5C%5C%5C%5Ch%3D100%5Ctimes%20%5Ctan%2830%29%5C%5C%5C%5Ch%3D57.73%5C%20m)
So, the height of the tower is 57.73 m.