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Kipish [7]
3 years ago
14

A skier of mass 70 kg is pulled up a slope by a motor-driven cable. The acceleration of gravity is 9.8 m/s 2 . How much work is

required to pull him 62.5 m up a 38.4 ◦ slope (assumed to be frictionless) at a constant speed of 3.77 m/s.
Physics
1 answer:
mote1985 [20]3 years ago
4 0

Answer:26.65 kJ

Explanation:

Given

mass of skier=70 kg

length of ramp=62.5 m

slope=38.4 ^{\circ}

speed=3.77 m/s

so net force on skier must be zero

Net work done will be change in Potential energy of skier

Potential Energy=mg(\Delta H)

\Delta H=62.5sin38.4=38.821 m

P.E.=70\times 9.81\times 38.82=26,658.88 J

P.E.=26.65 kJ

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3 years ago
When mapping the equipotentials on the plates with different electrode configurations you may find that some have significant ar
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v = 10 V and E = 2 10³ N/C

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The electrical potentials and the electric field at one point are related by the expression

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4 0
3 years ago
What is the answer to this question
Studentka2010 [4]

Answer:

0.11 m/s

Explanation:

From the question given above, the following data were obtained:

Initial displacement (d1) = 1.09 m

Final displacement (d2) = 2.55 m

Time (t) = 12.8 s

Average velocity =?

Next, we shall determine the total displacement (i.e change in displacement). This can be obtained as follow:

Initial displacement (d1) = 1.09 m

Final displacement (d2) = 2.55 m

Total displacement = d2 – d1

Total displacement = 2.55 – 1.09

Total displacement = 1.46 m

Finally, we shall determine the average velocity of the beetle. This can be obtained as follow:

Total Displacement = 1.46 m

Total time (t) = 12.8 s

Average velocity =?

Average velocity = Total Displacement / Total time

Average velocity = 1.46/12.8

Average velocity = 0.11 m/s

Thus, the average velocity of the beetle is 0.11 m/s

6 0
3 years ago
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