3 years ago

What is the force that acts against motion

1 answer:

3 0

It depends to the condition of the object or the situation of person. It could be friction, air resistance, water resistance.

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What is meant by input and output work

N76 [4]

Answer:

the x and y values

Explanation:

because on the table the x is the input and y is the output

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3 years ago

An object that is thrown straight up falls back to Earth. This is one-dimensional motion. (a) When is its velocity zero? (b) Doe

maw [93]

Answer:

Explanation:

(a) The velocity of object is zero when it is at maximum height.

(b) The direction of velocity changes as it starts moving downwards after it reaches the maximum height.

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3 years ago

Read 2 more answers

A student on an amusement park ride moves in circular path with a radius of 3.5 m once every 4.5 s. What is the tangential veloc

nata0808 [166]

Answer:

the tangential velocity of the student is 4.89 m/s.

Explanation:

Given;

the radius of the circular path, r = 3.5 m

duration of the motion, t = 4.5 s

let the student's tangential velocity = v

The tangential velocity of the student is calculated as follows;

$v = \frac{2\pi r}{t} \\\\v = \frac{2 \pi \times 3.5}{4.5} \\\\v = 4.89 \ m/s$

Therefore, the tangential velocity of the student is 4.89 m/s.

6 0

3 years ago

The bright, visible surface of the sun is called the

katrin2010 [14]

<span>The bright, visible surface of the Sun is called corona. The outermost layer of the Sun's atmosphere is called chromosphere.</span>

5 0

3 years ago

A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h

hram777 [196]

Answer:

$v_{2}=3.5 m/s$

Explanation:

Using the conservation of energy we have:

$\frac{1}{2}mv^{2}=mgh$

Let's solve it for v:

$v=\sqrt{2gh}$

So the speed at the lowest point is $v=7 m/s$

Now, using the conservation of momentum we have:

$m_{1}v_{1}=m_{2}v_{2}$

$v_{2}=\frac{1*7}{2}$

Therefore the speed of the block after the collision is $v_{2}=3.5 m/s$

I hope it helps you!

8 0

3 years ago