Explanation:
It is given that, a robot starts from a certain point and moves east for a distance of 5.0 meters, then goes north for 3.0 meters, and then turns west for 2.0 meters.
Let east is +x, west is -x north is +y.
When it moves east for a distance of 5.0 meters, it means (5,0)
When it goes north for 3.0 meters, and then turns west for 2.0 meters, it means (0,3) +(-2,0)
(a) x-y coordinates for the resultant vector is (3,3)
(b) The magnitude of the resultant vector for the robot is given by :

Explanation:
Hey, there!!
Single movable pulley has 2 VR because in single fixed pulley, load is supported with two segments of the string. It makes the effort distance double of the load distance. {As VR = No.of pulley used or number of rope segments that supports the load.}
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Explanation: A sneaker is a want because you don't actually need it to survive
<h2>
Answer: 1000 J</h2>
The Work
done by a Force
refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.
It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:
Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:
(1)
When they are not parallel, both directions form an angle, let's call it
. In that case the expression to calculate the Work is:
(2)
For example, in order to push the 200 N box across the floor, you have to apply a force along the distance
to overcome the resistance of the weight of the box (its 200 N).
In this case both <u>(the force and the distance in the path) are parallel</u>, so the work
performed is the product of the force exerted to push the box
by the distance traveled
. as shown in equation (1).
Hence:
>>>>This is the work
Answer:
4.3 m/sec
Explanation:
Here height of cliff = y = 37.6 m
Gravitational acceleration = g = 9.8 m/sec2
vi = 0 m/s
Let's find the time which the diver will take if jumps from there!
Using formula
y = vit+1/2gt2
==> 37.6= 0 + 0.5 ×9.8×
==>
=
==> t = 2.8 sec
In this time the diver has to cover a horizontal distance of 12.12 m
If x = 12.12 m is the horizontal distance to be covered then using
x= Vx × t
==> Vx = x/t
==> Vx= 12.12/2.8 = 4.3 m/s