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3 years ago

A car traveling 90km/hr is 100 m behind a truck traveling 50km/hr. How long will it take the car to reach the truck?

2 answers:

5 0

Since both these cars are traveling as an assumed constant rate, you can imagine them as not moving at all to make the problem easier conceptually. The distance between the cars will also remain constant. First, convert the units km/hr into m/s: 90/3.6= 25 m/s; 50/3.6=13.89 m/s. The difference between these two speeds is 11.11 m/s. Now use the equation: velocity= distance/time. 11.11= 100/time; solve for time and you should get 9.0009 seconds

AlexFokin [52]3 years ago

4 0

The faster car behind is catching up/closing the gap/gaining on
the slow truck in front at the rate of (90 - 50) = 40 km/hr.

At that rate, it takes (100 m) / (40,000 m/hr) = 1/400 of an hour
to reach the truck.

(1/400 hour) x (3,600 seconds/hour) = 3600/400 = <em>9 seconds</em>, exactly

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A long jumper can jump a distance of 7.4 m when he takes off at an angle of 45° with respect to the horizontal. Assuming he can

GenaCL600 [577]

Answer:

0.02 m

Explanation:

R₁ = initial distance jumped by jumper = 7.4 m

R₂ = final distance jumped by jumper = ?

θ₁ = initial angle of jump = 45°

θ₂ = final angle of jump = 42.9°

$v$ = speed at which jumper jumps at all time

initial distance jumped is given as

$R_{1}=\frac{v^{2}Sin2\theta _{1} }{g}$

final distance jumped is given as

$R_{2}=\frac{v^{2}Sin2\theta _{2} }{g}$

Dividing final distance by initial distance

$\frac{R_{2}}{R_{1}}=\frac{Sin2\theta _{1}}{Sin2\theta _{2}}$

$\frac{R_{2}}{7.4}=\frac{Sin2(42.9)}{Sin2(45))}$

$R_{2} =7.38$

distance lost is given as

d = $R_{1} - R_{2}$

d = 7.4 - 7.38

d = 0.02 m

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2 years ago

A dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to a frequency of 18 rpm,

puteri [66]

Answer:

F = 176.175 N

Explanation:

given,

radius of merry - go - round = 2.7 m

mass of the disk = 800 kg

speed of the merry- go-round = 18 rpm

= 18 $\dfrac{2\pi }{60}$

= 1.88 rad/s

time = 13 s

mass of two children = 25 kg

ω = ω₀ + α t

1.88 = 0 + α(13)

α = 0.145 rad/s²

we know

τ = I α

so,

$I = \dfrac{1}{2}MR^2+ 2 MR^2$

$I = \dfrac{1}{2}\times 800 \times 2.7^2+ 2\times 25\times 2.7^2$

$I = 3280.5 kg.m^2$

τ = I α

τ = 3280.5 x 0.145

τ = 475.67 N m

τ = F x r

475.67 = F x 2.7

F = 176.175 N

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3 years ago

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umka21 [38]

Solid, because the atoms maintain their form and do not take the shape of their container. The particles share tight, close bonds due to this set shape

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3 years ago

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3) While flying horizontally in an airplane, you notice that a string dangling from the overhead

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Answer:

Explanation:

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