Answer:
L = 2.83 J.s
Explanation:
The formula for the angular momentum of the stone is given as follows:
L = mvr
where,
L = angular momentum of the stone = ?
m = mass of the stone = 0.1 kg
v = linear velocity of the stone = rω
r = radius of circular path = 1.5 m
ω = angular speed of the stone = (2 rev/s)(2π rad/1 rev) = 4π rad/s
Therefore,
L = mvr = m(rω)r
L = mr²ω
using values, we get:
L = (0.1 kg)(1.5 m)²(4π rad/s)
<u>L = 2.83 J.s</u>
Convert cm into meters,
50/100=0.5m
work done= 10x0.5
=5J
we dont consider the weight of the spring as it acts downwards.
Answer:
330Ns
Explanation:
Given parameters:
Mass of the box = 5kg
Initial velocity = 0m/s
Force applied = 15N
Time = 22s
Unknown:
Impulse = ?
Final momentum = ?
Solution:
The impulse of the box can be determined using the expression below:
Impulse = Force x time
Impulse = 15 x 22 = 330Ns
The final momentum is the same as this impulse
The impulse and the final momentum is 330Ns
Answer:
i think it might be c but i know its not A or B and im
on the fence for D so the best answer would be C
Explanation:
