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3 years ago

5

A semicircle has a diameter of 17.6 cm.

1 answer:

Ray Of Light [21]3 years ago

7 0

Answer:

B. 45.23 cm

Step-by-step explanation:

perimeter of the figure

$=\frac{1}{2}\pi d+d$

$=\frac{1}{2}\times 3.14\times 17.6 +17.6$

$=\frac{1}{2}\times 55.264 +17.6$

$=27.632 +17.6$

$=45.232$

$=45.23\: cm$

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Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)<br>

Pie

Answer:

Gradient: m = 3

Step-by-step explanation:

m = change in y/change in x

m = $\frac{Y2-Y1}{X2-X1}$

m = $\frac{9-(-3)}{6-(2)}$

m = 12/4

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3 years ago

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3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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3 years ago

-9 divided by 5/8 equals

DedPeter [7]

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2 years ago

-2x + y = 1<br> -4x + y = -1<br> Solve the following system of equation

andre [41]

Answer:

x = 2 and y = 5

Step-by-step explanation:

2x = 2

x = 2

-4 + y = 1

y = 5

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