To increase the rate of a reaction, you can either do any of the following:
-increase the temperature
-increase concentration of the aqueous reactant
-increase pressure of the gas
-use a catalyst
-increase surface area of the solid reactant
From these, the engineer should therefore do C. Adding a catalyst speeds up the reaction without really joining the reaction.
<span>An enzyme is a protein that acts as a catalyst in a chemical reaction that takes place in a living thing. <em>It is true.</em></span>
Answer:
2 moles of SO₂
Explanation:
Equation of reaction
H₂S + 3H₂SO₄ → 4H₂O + 4SO₂
From the equation of reaction above,
1 mole of H₂S will produce 4 moles of SO₂
1 mole of H₂S = 4 moles of SO₂
0.5moles of H₂S = zmoles of SO₂
z = (0.5*4) / 1
z = 2 moles of SO₂
0.5 moles of H₂S will produce 2 moles of SO₂
Answer:
47.1 L.
Explanation:
- To solve these problems, we can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 234.0 kPa/101.325 ≅ 2.31 atm) .
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 3.9 mol).
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas in K (T = 67.0 °C + 273.15 = 340.15 K).
The volume of the gas = nRT/P.
<em>∴ V = nRT/P </em>= (3.9 mol)(0.082 L.atm/mol.K)(340.15 K)/(2.31 atm) = <em>47.1 L.</em>
