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3 years ago

Every female bear has 3 baby cubs. What is the constant of proportionality for the ratio of cubs to female bears?

Mathematics

2 answers:

lana66690 [7]3 years ago

6 0

It would be b correct me if I’m wrong

KatRina [158]3 years ago

5 0

Answer:

Step-by-step explanation:

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Brianne's town is building a pool based on a scale drawing that is 20 centimeters by 10 centimeters and uses the scale 1 cm:250

kiruha [24]

Answer:

$A=1250m^2$

Step-by-step explanation:

From the question we are told that

Dimension of drawing

20 centimetres by 10 centimetres

Scale of drawing

1 cm:250 cm

Generally the the Main dimension of the pool is mathematically given as

$L=length\ of\ scaled\ pool*250 cm\\B=length\ of\ scaled\ pool*250 cm\\L=20*250=5000 cm=50m\\B=10*250=2500 cm=25m$

Therefore Area Aof main pool is mathematically given as

$A=50m*25m=1250 m^2$

$A=1250m^2$

4 0

3 years ago

If b=2 , what is the value of the 18/2 + 3b

Gemiola [76]

Answer:

Step-by-step explanation:

7 0

3 years ago

MP Find the Error Katrina states that

nika2105 [10]

Answer:

3.5 X 10^4 < 2.1 x 10^6

Step-by-step explanation:

3.5 X 10^4 < 2.1 x 10^6

The first thing we look at is the exponent

10 ^4 is less than 10^6

10000 < 1000000

If the exponents are the same, then we look at the numbers out front

4 0

3 years ago

3-4 litros de jugo de frutilla 1 y 1-2 litros de jugo de manzana 1-8 litro de jugo consentrado de limón . 1 y 1-2 litro de agua.

Neko [114]

Answer:

Hay 3,875 litros de jugo multifrutal.

Step-by-step explanation:

<em>(Se asume que el problema fue propuesto en un país distinto a los Estados Unidos, razón por la cual se emplea las reglas del Sistema Internacional.)</em>

La capacidad de jugo multifrutal en el bidón se obtiene con la mezcla de cada jugo frutal y se logra mediante la suma de cada capacidad. A partir del enunciado, tenemos que la capacidad del jugo multifrutal es:

$V = \frac{3}{4}\,L + 1\,\frac{1}{2}\,L + \frac{1}{8}\,L + 1\,\frac{1}{2}\,L$