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QveST [7]
3 years ago
7

How would you prove air contains carbon dioxide??​

Physics
2 answers:
jarptica [38.1K]3 years ago
7 0

Answer:

by using lime water

Explanation:

if carbon dioxide is bubbled through lime water then the water turns from clear to a milky, cloudy color. this is why when used in a simple respirometer it can show that there's more carbon dioxide in exhaled air compared to inhaled air

Alja [10]3 years ago
3 0
By showing the molecules in air that someone just exhaled
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How does luminosity and temperature correlate to the mass of a star?
Norma-Jean [14]
Stars with higher luminosity and temperature have higher masses as massive stars require higher core temperatures to remain stable.
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3 years ago
When a mule stops suddenly, the packages
Flauer [41]
The answer here would be the first law of motion. An object in motion will stay in motion unless acted upon by another force.
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3 years ago
How are electricity and magnets connected?
Stella [2.4K]

Answer:

Magnets are employed to generate electricity.

Explanation:

Magnets' characteristics are employed to generate electricity. Electrons are pulled and pushed by moving magnetic fields. When you move a magnet around a coil of wire, or a coil of wire around a magnet, the electrons in the wire are pushed out and an electrical current is created.

3 0
3 years ago
Read 2 more answers
A movie stunt performer is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough
Julli [10]

Answer:

1125.66956 N

Explanation:

m = Mass of stunt performer

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of the swing = 7 m/s

T = Tension

r = Radius of the swing = Length of vine = 11.5 m

From the free body diagram

T-mg-m\frac{v^2}{r}=0\\\Rightarrow T=mg+m\frac{v^2}{r}\\\Rightarrow T=m(g+\frac{v^2}{r})\\\Rightarrow T=80(9.81+\frac{7^2}{11.5})\\\Rightarrow T=1125.66956\ N

The minimum tension force the vine must be able to support without breaking is 1125.66956 N

7 0
3 years ago
An object carries a +15.5 uC charge.
abruzzese [7]

Answer:

3.67 N

Explanation:

From the question given above, the following data were obtained:

Charge of 1st object (q₁) = +15.5 μC

Charge of 2nd object (q₂) = –7.25 μC

Distance apart (r) = 0.525 m

Force (F) =?

Next, we shall convert micro coulomb (μC) to coulomb (C). This can be obtained as follow:

For the 1st object

1 μC = 1×10¯⁶ C

Therefore,

15.5 μC = 15.5 × 1×10¯⁶

15.5 μC = 15.5×10¯⁶ C

For the 2nd object:

1 μC = 1×10¯⁶ C

Therefore,

–7.25 μC = –7.25 × 1×10¯⁶

–7.25 μC = –7.25×10¯⁶ C

Finally, we shall determine the force. This can be obtained as follow:

Charge of 1st object (q₁) = +15.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.25×10¯⁶ C

Distance apart (r) = 0.525 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 15.5×10¯⁶ × 7.25×10¯⁶ / 0.525²

F = 3.67 N

Therefore, the force on the object is 3.67 N

4 0
3 years ago
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