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frozen [14]
3 years ago
14

If a spectral line from a distant star is measured to have a wavelength of 497.15 nm, but is normally at 497.22 nm how fast (spe

ed, not velocity) with respect to the Earth is the star moving in m/s
Physics
2 answers:
Aliun [14]3 years ago
6 0

Answer:

v = -4.22 x 10⁻⁴ m/s

Explanation:

given,

measured wavelength = 497.15 nm

Normally wavelength = 497.22 nm

Change in wavelength

Δ λ = 497.15 - 497.22

Δ λ = -0.07 nm

using Doppler's equation

\dfrac{\Delta \lambda}{\lambda}=\dfrac{v}{c}

v is the speed of the star

c is the speed of light

\dfrac{-0.07\ nm}{497.22\ nm}=\dfrac{v}{3\times 10^8}

      v = -4.22 x 10⁻⁴ m/s

Speed of the star moving is equal to v = -4.22 x 10⁻⁴ m/s

KiRa [710]3 years ago
5 0

Answer:

The speed is 42210 m/s.

Explanation:

Given that,

Normally wavelength \lambda= 497.22\ nm

Observed spectral line \Delta \lambda+\lambda= 497.15\ nm

We need to calculate the change in wavelength

Using formula of wavelength

\Delta \lambda+\lambda=497.15

\Delta\lambda+497.22=497.15

\Delta\lambda=497.15-497.22

\Delta\lambda=−0.07\ nm

We need to calculate the value of z

Using formula for z

z=\dfrac{\Delta\lambda}{\lambda}

Put the value into the formula

z=\dfrac{-0.07}{497.22}

z=−0.0001407

We need to calculate the speed

Using formula of speed

v=c\times z

Put the value into the formula

v=3\times10^{8}\times0.0001407

v=42210\ m/s

Hence, The speed is 42210 m/s.

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