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3 years ago

Formula for displacement

1 answer:

8 0

The original velocity multiplied by time plus<span>one half the </span>acceleration<span> multiplied by the square of time</span>

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How many electrons must be removed from each of two 4.85-kg copper spheres to make the electric force of repulsion between them

VladimirAG [237]

Answer:

$n=2.611*10^{9}electrons$

Explanation:

Given data

mass of copper m=4.85 kg

charge of electron qe= -1.6×10⁻¹⁹C

To find

Number of electron n must be removed

Solution

Equate the magnitude of electric force Fe of repulsion between two two spheres to the magnitude of gravitational force of attraction between them

$F_{e}=F_{g}\\ k\frac{q_{e}q_{e}}{r^{2} }=G\frac{m^{2} }{r^{2} }\\ k(q_{e})^{2}=Gm^{2}\\$

where q is charge of each sphere which is equal to number n of removed electrons multiplied by each charge qe

$k(nq_{e})^{2}=Gm^{2}\\n=\sqrt{\frac{Gm^{2}}{k(q_{e})^{2}} }\\ n=\sqrt{\frac{(6.67*10^{-11}N.m^{2}/kg^{2})(4.85kg)^{2}}{(8.99*10^{9}N.m^{2}/C^{2} )(1.6*10^{-16}C)^{2}} }\\n=2.611*10^{9}electrons$

3 0

4 years ago

A dock worker applies a constant horizontal force of 80.5 N to a block of ice on a smooth horizontal floor. The frictional force

Eddi Din [679]

Answer:

(a). The mass of the block of ice is 62.8 kg.

(b). The distance is 24.192 m.

Explanation:

Given that,

Horizontal force = 80.5 N

Distance = 13.0 m

Time = 4.50 s

(a). We need to calculate the acceleration of the block of ice

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$13=0+\dfrac{1}{2}\times a\times(4.50)^2$

$a=\dfrac{13\times2}{(4.50)^2}$

$a=1.28\ m/s^2$

We need to calculate the mass of the block of ice

Using formula of force

$F = ma$

$m=\dfrac{F}{a}$

Put the value into the formula

$m=\dfrac{80.5}{1.28}$

$m=62.8\ kg$

(b). If the worker stops pushing at the end of 4.50 s,

We need to calculate the velocity

Using equation of motion

$v =u+at$

Put the value into the formula

$v=0+1.28\times4.50$

$v=5.76\ m/s$

We need to calculate the distance

Using formula of distance

$v = \dfrac{d}{t}$

$d=v\times t$

Put the value into the formula

$d=5.76\times4.20$

$d=24.192\ m$

Hence, (a). The mass of the block of ice is 62.8 kg.

(b). The distance is 24.192 m.

5 0

3 years ago

the magnitude of the electrical force acting between a +2.4x10-8c charge and 1+1.8x10-6 charge that are separated by 1.008m is

Temka [501]

Answer:

3.83×10¯⁴ N

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +2.4x10¯⁸ C

Charge 2 (q₂) = +1.8x10¯⁶ C

Distance apart (r) = 1.008 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

The magnitude of the electrical force acting between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²

F = 0.0003888 / 1.016064

F = 3.83×10¯⁴ N

Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N

5 0

3 years ago

A football player kicks a 0.94 kg football with a force of 2.4 N. Calculate the acceleration of the football as the player kicks

Anon25 [30]

Hello, I hope this helps :)
So the equation to figure these kinds of questions is F=MA
F refers to force, which in this situation F would be 2.4
M refers to mass, mass would be 0.94
A refers to acceleration, which we are trying to figure out
So if we put in the information we know into the equation, it is now 2.4=0.94*A
So with that equation we can figure that 2.4 divided by 0.94 equals A
So 2.4/0.94= 2.553191489362 :'D
Don't worry, the rounded and correct answer is 2.6
Have a nice day =)

7 0

3 years ago

Read 2 more answers

Express newton pascal joule and watt in fundamental unit

Nadya [2.5K]

i added an image. i hope it helped :)

3 0

3 years ago