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3 years ago

Formula for displacement

1 answer:

8 0

The original velocity multiplied by time plusone half the acceleration multiplied by the square of time

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The density of water is 1.00 g/cm3. The density of ethanol is 0.80 g/cm3. What is the volume of ethanol, in cm3 that has the sam

eduard

Explanation:

Given that,

The density of water is 1 g/cm³

The density of ethanol is 0.8 g/cm³

We need to find the volume of the ethanol that has the same mass as 100 cm³ of water.

Density=mass/volume

For water,

$d=\dfrac{m}{V}\\\\m=dV\\\\m=1\ g/cm^3\times 100\ cm^3\\\\m=100\ g$

For ethanol,

$d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{100\ g}{0.8\ g/cm^3}\\\\V=125\ cm^3$

Hence, 125 cm³ of ethanol has the same mass as 100 cm³ of water.

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3 years ago

If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.55 x 10-4 T) at a distance of 25

antiseptic1488 [7]

we are given in the problem the following dimensions or specifications
B = 0.000055 T r = 0.25 m constant mu0 = 4*pi*10-7

The formula that is applicable from physics is
B = mu0*I/(2*pi*r) I = 2*B*pi*r/mu0 I = 68.75 Amperes

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3 years ago

Read 2 more answers

Oxygen atoms have six electrons in their outer shells. When two oxygen atoms bond they will form a(n) _____ bond by _____ their

s344n2d4d5 [400]

Peptide bond by negative

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4 years ago

All atoms contain negatively charged ____________ that orbit around a positively charged nucleus.

S_A_V [24]

Answer: Electron

In atom, there are proton and neutron inside the nucleus and electron which was moving in orbit outside of the nucleus. The electron is a negatively charged, a proton is positively charged and neutron is neutral. Since there are only proton and neutron in the nucleus it's become positively charged.

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3 years ago

A box of negligible mass rests at the left end of a 2.00-m, 25.0-kg plank (Fig. P11.43). The width of the box is 75.0 cm, and sa

Sati [7]

Answer:

Required mass of sand is 20 kg

Explanation:

Given:

Mass of the plank = 25 kg

Distance of the Center of gravity of the Plank from the fulcrum = $\frac{2}{2}-0.50 = 0.5m$

Distance of the Center of gravity of the sand box from the fulcrum = $\frac{2}{2}-\frac{0.75}{2}= 0.625m$

Balancing the torque due to the plank and the sand box with respect to the fulcrum

Torque = Force × perpendicular distance

thus, we get

(25 × g) × 0.5 = weight of sand × 0.625

where, g is the acceleration due to gravity

(25 × g) × 0.5 = (mass of sand × g) × 0.625

mass of sand = 20 kg

Hence, the required mass of the sand is 20 kg

8 0

3 years ago