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Snezhnost [94]
3 years ago
15

How many dots must be added to the symbol to properly represent a standard nitrogen ion? A) 1 B) 3 C) 5 D) 8

Physics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

D

Explanation:

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What will happen if the value of g that is 9.8m/s^2 becomes zero???
quester [9]

Answer:

everything will fly about endlessly

Explanation:

the gravitational mass or whatever is now zero, this implies that object that are attracted to each other would no longer gain that attraction due to the absence of the force of attraction putting everything in place

8 0
3 years ago
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high school physics, no need detail explain, just give the answer, but you have to make sure thank you
andrey2020 [161]

Answer:

approximately 30 degrees

Explanation:

If it takes the cannonball 2 seconds to reach the maximum height, we can use the analysis of the vertical component of the velocity and the fact that the acceleration of gravity is the one acting opposite to this initial vertical component (v_y) of the velocity. We know as well that at the top of the trajectory, the vertical component of the velocity is zero, and then the movement starts going down in it trajectory. So, the final velocity for the first part of the ascending movement is zero, giving us the following equation for the velocity under an accelerated movement (with acceleration of gravity "g" acting):

v_f=v_i-a\,t\\v_f=v_y-g\,t\\0=v_y-9.8\,*\,2\\v_y=9.8\,*\,2=19.6 \frac{m}{s}

By knowing the vertical component of the initial velocity (19.6 m/s), and the actual magnitude of the total initial velocity (40 m/s), we can calculate what angle was the initial velocity vector forming above the horizontal. We use for such the fact that the sine of the angle relates the opposite side of a right angle triangle with the hypotenuse, and solve for the angle using the arcsin function:

sin(\theta)=\frac{opp}{hyp} \\sin(\theta)=\frac{19.6}{40}\\\theta=arcsin(\frac{19.6}{40})\\\theta=29.34^o

which tells us that the closer answer shown is 30^o

7 0
4 years ago
Which type of modulation is applied to radio-controlled toys?
Alenkinab [10]

Pulse type of modulation is applied to radio-controlled toys, therefore the correct answer is option D.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

Toys controlled by remote control operate by emitting infrared radiation. These infrared rays have a frequency of 34–48 kilo Hertz.

Different types of modulations, such as frequency and amplitude modulation for transmitting and receiving video and music, are employed for other reasons.

Thus, the Pulse-type of modulation is applied to radio-controlled toys, therefore the correct answer is option D.

Learn more about frequency from here

brainly.com/question/14316711

#SPJ1

6 0
2 years ago
A neutron star is an extremely dense, rapidly spinning object that results from the collapse of a massive star at the end ofits
Westkost [7]

Answer:

(a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Explanation:

Given that,

Mass of neutron M_{n}= 13M_{s}

Density of neutron \rho=4.8\times10^{17}\ kg/m^3

(a). We need to calculate the rotational inertia

Using formula of rotational inertia  for sphere

I=\dfrac{2}{5}MR^2...(I)

We know that,

\rho=\dfrac{M}{V}

Put the value of volume

\rho=\dfrac{3M_{n}}{4\pi R^3}

R^2=(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value of R in equation (I)

I=\dfrac{2}{5}\times M_{n}\times(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value into the formula

I=\dfrac{2}{5}\times(13\times2\times10^{30})^{\frac{5}{3}}\times(\dfrac{3}{4\pi\times(4.8\times10^{17})})^{\frac{2}{3}}

I=5.72\times10^{39}\ kg m^2

The rotational inertia is 5.72\times10^{39}\ kg m^2.

(b). We need to calculate the magnitude of the magnetic torque

Using formula of torque

\tau=I\times \alpha

Put the value into the formula

\tau=5.72\times10^{39}\times5.6\times10^{-5}

\tau=3.20\times10^{35}\ N-m

The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Hence, (a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

4 0
3 years ago
If you are in a car at a stop sign and then the driver
SVEN [57.7K]

Answer:

it wont be because the hand brake would be on

4 0
3 years ago
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