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3 years ago

9

Whats an example of a linear relationship?

2 answers:

Luda [366]3 years ago

6 0

Answer:

For example a common equation, y=mx+b y = m x + b,is a linear function because it meets both criteria with x and y as variables and m and b as constants.

Step-by-step explanation:

kramer3 years ago

5 0

It is a straight line in a graphical format.

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A recipe for a cookie batch calls for 5/8 cup of flour. There are three and three-fourths cups of flour in a bag in the cupboard

WITCHER [35]

Answer:

So a batch is 5/8

There are THREE 3/4th cups of flour in the cupboard.

So 3 three fourths so basically
3/4 * 3 = 9/4 or

3/4 + 3/4 + 3/4 = 9/4

9/4 and each batch is 5/8.
9/4 ÷ 5/8 = 72/20 or 3 1/10

3 batches of cookies.

3 0

2 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

Carmelita used the multiplication table below to write ratios that are equivalent to 3/7 . One number is missing from the equiva

amm1812

Answer:

49

Step-by-step explanation:

5 0

3 years ago

Of the following, which reads the same forwards, backwards, and upside down (when viewed on a calculator screen)?

Feliz [49]

Answer: D 1881

Step-by-step explanation: 6889 and 1961 don't read the same forwards and backward. 1991 upside down is 1661. So, only 1881 works

4 0

2 years ago

What is the mean of the set of numbers, {–11, 22, –2, –3}? A. –6.5 B. –1.5 C. 1.5 D. 6.5

tekilochka [14]

$\dfrac{-11+22+(-2)+(-3)}{4}=\dfrac{22-16}{4}=\dfrac{6}{4}=\fbox{1.5}\to\fbox{C.}$

7 0

3 years ago

Read 2 more answers