Answer:
∠ BDA = 55° , ∠ BCA = 70°
Step-by-step explanation:
∠ BOA = 360° - 250° = 110° ( angles round a point )
The central angle is twice the angle on the circle, subtended on the same arc
∠ BDA = ∠ BOA =
× 110° = 55°
OBCA is a tangent kite
Opposite angles sum to 180° , then
∠ BCA = 180° - ∠ BOA = 180° - 110° = 70°
here u go! i hope this is correct :)
Answer:
The angle of elevation of the plane measured from Ahmed is approximately 36.67°
Step-by-step explanation:
The given parameters of the float plane are;
The height of the float plane above the water, y = 350 m
The horizontal distance of the float plane from Ahmed, x = 470 m
Given that Ahmed is sitting on the dock, by the water, by trigonometric ratios, we have;
The height of the float plane, the distance of the plane from Ahmed and the line of sight forming the angle of elevation of the plane measured from Ahmed, form a right triangle
Therefore
Where;
θ = The angle of elevation of the plane measured from Ahmed
y = The leg of the right triangle opposite the reference angle
x = The leg of the right adjacent to reference angle
Therefore;
θ = arctan(y/x) which gives;
θ = arctan(350/470) ≈ 36.67°
The angle of elevation of the plane measured from Ahmed, θ ≈ 36.67°.