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3 years ago

Compare and contrast expanding and simplifying

Mathematics

2 answers:

Pavel [41]3 years ago

7 0

Answer:

With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.

Step-by-step explanation:

Tasya [4]3 years ago

6 0

Answer: With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.

Step-by-step explanation: Sample Response

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sergejj [24]

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3 years ago

In questions 1a-1d, choose yes or no to tell if the number 1/2 will make each equation true.

Tresset [83]

Answer:

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3 years ago

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3 years ago

On a coordinate plane, 2 cube root functions are shown. Function f (x) goes through (negative 3, negative 1.5), has an inflectio

Strike441 [17]

Using translation concepts, it is found that the equation that represents the graph of g(x) is:

$g(x) = \sqrt[3]{x + 2}$ .

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, we have that g(x) is a shift left of 2 units of f(x), hence:

$f(x) = \sqrt[3]{x}$

$g(x) = f(x + 2) = \sqrt[3]{x + 2}$

More can be learned about translation concepts at brainly.com/question/4521517

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2 years ago

the length of a rectangle is 9 inches less than twice the width. if the perimeter of the rectangle is 84 inches, find the dimens

Alexus [3.1K]

translate each statement into mathematical language

length is nine inches less than twice width. L = 2W - 9

perimeter is 84 inches 2L +2W = 84

Substitute the expression for L (2W-9) for L in the second equation resulting in the follwing

2(2W-9) + 2W = 84

4W - 18 + 2W = 84

(4W+2W) = 84+18

6W = 102

W = 102/6 = 51/3

L = 2(51/3) - 9

= L= 17-9

L=6

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4 years ago