<h2>
Hello!</h2>
The answer is:
There are 732.24 grams of Dinitrogen Pentoxide in 6.78 moles of the same compound.
<h2>
Why?</h2>
The dinitrogen pentoxide, or nitrogen pentoxide, is a rare salt that consists of anion and cations, and it's an important compound when preparing some kinds of explosives.
So, to answer the question, first, need to look for the molecular formula of the dinitrogen pentoxide, then, use it to calculate the mass in gram of 6.78 moles of the same compound.
The dinitrogen pentoxide formula is:
Where, the molar mass of each element are:
Calculating the molar mass of the compound, we have:
Now, calculating what is the mass of 6.78 of , we have:
So, there are 732.24 grams of Dinitrogen Pentoxide in 6.78 moles of the same compound.
Have a nice day!
Yes, it does matter... you pour Acid into water and not water in Acid... because when you pour water in acid it may splash out
A polyatomic ion is a molecuar ion that is composed of more than one element. The elements in this molecule are chemically bonded and is a charge chemical species. These atoms act as a simgle unit. Examples are C2H3O2^- (acetate), CO3^2- (carbonate) and CrO4^2- (chromate).
Answer:
9.28 g/L
Explanation:
We will be using the ideal gas law to solve this problem:
PV = nRT where P is the pressure (atm)
V is the volume (L)
R is the gas constant 0.08205 Latm/Kmol
T is the temperature (K)
n is the number of moles
The number of moles is the mass divided by the molecular weight, and from here we can solve for the density. (Note here we use the atomic weight of radon since its is a monoatomic noble gas)
PV = m/AW RT ⇒ P = (m/V ) RT/AW ⇒ P AW /RT =D
0.950 atm x 222.0 g/mol / [( 0.08205 Latm/Kmol ) x 277 K ] = D
9.28 g/L = D
<span>Firstly, we know that M= m/n, the main formula which shows the relationship
between m, n, and M. The nknown compound contains only carbon, hydrogen, and
oxygen, so we can get n(C)=m/M, from M(C)=
m(C)/n (C), besides the stoechiometric
equality, we have </span>
n( C)= m(C)/M(C ) = m(CO2)/ M(CO2)=11/44, because m(CO2)=11.0,
M(CO2)=44.01
so n(C )= 0.24moles,