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AlladinOne [14]
2 years ago
12

In these chemical compounds, c is for carbon, o is for oxygen, n is for nitrogen, and k is for potassium. Which chemical compoun

d is organic?.
Chemistry
1 answer:
Jet001 [13]2 years ago
8 0

Answer:

carbon because organic compounds are made up of hydrogen and carbon

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Which of the following events takes place in the Kreb entry phase (acetyl COA from pyruvate)?
Aneli [31]

Answer:

Alphabet C :NADH is oxidized,CO2 is reduced

5 0
3 years ago
Blast furnaces extra pure iron from the Iron(IIl)oxide in iron ore in a two step sequence. In the first step, carbon and oxygen
OLga [1]

Answer:

5.9 kg  

Explanation:

We must work backwards from the second step to work out the mass of oxygen.

1. Second step

Mᵣ:                                     55.84

            Fe₂O₃ + 3CO  ⟶  2Fe  +  3CO₂

m/kg:                                    7.0

(a) Moles of Fe

\text{Moles of FeO} = \text{7000 g Fe} \times \dfrac{\text{1 mol Fe}}{\text{55.84 g Fe}} = \text{125 mol Fe}

(b) Moles of CO

\text{Moles of CO} = \text{125 mol Fe} \times \dfrac{\text{3 mol CO}}{\text{2 mol Fe}} = \text{188 mol CO}

However, this is the theoretical yield.

The actual yield is 72. %.

We need more CO and Fe₂O₃ to get the theoretical yield of Fe.

(c) Percent yield

\begin{array}{rcl}\text{Percent yield} &=& \dfrac{\text{ actual yield}}{\text{ theoretical yield}} \times 100 \, \%\\\\ 72. \, \% & = & \dfrac{\text{188 mol}}{\text{actual yield}} \times 100 \,\%\\\\0.72 &= &\dfrac{\text{188 mol}}{\text{actual yield}}\\\\\text{Actual yield} & = & \dfrac{\text{188 mol}}{0.72}\\& = & \textbf{261 mol}\\\\\end{array}

We must use 261 mol of CO to get 7.0 kg of Fe.

2. First step

Mᵣ:                32.00

            2C   +  O₂   ⟶  2CO

n/mol:                             261

(a) Moles of O₂

\text{Moles of O}_{2} = \text{261 mol CO} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol CO}} = \text{131 mol O}_{2}

(b) Mass of O₂

\text{Mass of O}_{2}= \text{131 mol O }_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol  O}_{2}} = \text{4180 g O}_{2}

However, this is the theoretical yield.

The actual yield is 71. %.

We need more C and O₂ to get the theoretical yield of CO.

(c) Percent yield

\begin{array}{rcl}71. \, \% & = & \dfrac{\text{188 mol}}{\text{actual yield}} \times 100 \,\%\\\\0.71 &= &\dfrac{\text{4180 g}}{\text{actual yield}}\\\\\text{Actual yield} & = & \dfrac{\text{4180 g}}{0.71}\\\\& = & \text{5900 g}\\& = & \textbf{5.9 kg}\\\end{array}

We need 5.9 kg of O₂ to produce 7.0 kg of Fe.

6 0
4 years ago
Which law is used to determined the relationship between the volume and the number of moles
alukav5142 [94]

Answer:

Avogadro's Law

Explanation:

Avogadro's number (6.23 x 10^23)

Avogadro's law states that the volume and number of moles are proportional if pressure and temp remain constant.

8 0
4 years ago
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When calcium chloride is dissolved in water, to which end of the adjacent water molecules will a calcium ion be attracted? the o
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Ca ionises into Ca^2+. Ca^2+ will be attracted to O^2- ions in the water, since opposite charges attract. (Hydrogen in water forms H^+)
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Who discovered the first real evidence of the big bang?
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The scientist who discovered the first real evidence of the big bang was EDWIN HUBBLE.
Astronomer Edwin Hubble was an American astrophysicist. He contributed in so many ways to humanity during his lifetime. One of his contribution is that, his observation showed the existence of galaxies that are far beyond the milky way; these galaxies were moving away from one another. This observation serves as a concrete evidence for the big bang theory, which explain the origin of the universe. 
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