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Anettt [7]
4 years ago
12

What is the independent variable?

Chemistry
1 answer:
olganol [36]4 years ago
6 0
X is always the independent variable
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Use the equation below to determine how many grams of CO are needed to react with an excess of Fe2O3 to produce 104.9 g Fe? You
patriot [66]

Answer:

1.40 * 10 ^3 g

Explanation:

7 0
3 years ago
Read 2 more answers
The chemical equation represents a reaction between ammonia and oxygen to form nitrogen monoxide and water. 4 N H 3 ( g ) + 5 O
Vilka [71]

The limiting reagent : NH₃

<h3>Further explanation</h3>

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactants become a limiting reactant

Reaction

4NH₃(g)+5O₂(g)⇒4NO(g)+6H₂O(g)

mol NH₃ :

\tt \dfrac{4.5}{17}=0.265

mol O₂ :

\tt \dfrac{15.8}{32}=0.494

mol ratio

NH₃ :

\tt \dfrac{0.265}{4}=0.06625

O₂ :

\tt \dfrac{0.494}{5}=0.0988

Limiting reactants : NH₃ (smaller ratio)

3 0
3 years ago
What is the freezing point of an aqueous solution that boils at 103.7 degrees Celsius?
inna [77]
For this, we use equations from the colligative properties of solutions specifically boiling point elevation and freezing point depression. The equations for these are expressed as:

ΔTb = kb m

where k is a boiling point elevation constant and m is the concentration in terms of molality

ΔTf = kf m 

where k is a freezing point elevation <span>constant and m is the concentration in terms of molality
</span>
We use both expression to solve for the freezing point. For this case, concentration is the same. The equation will then be:

ΔTf = kf ( ΔTb / kb )
0-Tf = 1.86 (103.7 - 100 / 0.512 )
Tf = -13.4°C
7 0
3 years ago
Given that E°red = -1.66 V for Al3+/ Al at 25°C, find E° and E for the concentration cell expressed using shorthand notation bel
lbvjy [14]

Answer:

E° = 0.00 V

E = 0.079 V

Explanation:

We can identify both half-reactions occurring in a concentration cell.

Anode (oxidation): Al(s) → Al³⁺(1.0 × 10⁻⁵ M) + 3 e⁻   E°red = -1.66 V

Cathode (reduction): Al³⁺(0.100 M) + 3 e⁻ → Al(s)     E°red = -1.66 V

The global reaction is:

Al(s) + Al³⁺(0.100 M) → Al³⁺(1.0 × 10⁻⁵ M) + Al(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an = -1.66 V - (-1.66 V) = 0.00 V

To calculate the cell potential (E) we have to use the Nernst equation.

E = E° - (0.05916/n) .log Q

where,

n: moles of electrons transferred

Q: reaction quotient

E = 0.00 V - (0.05916/3) .log (1.0 × 10⁻⁵/0.100)

E = 0.079 V

4 0
3 years ago
What unit is used to measure cell potential?
Lilit [14]

Volt is the unit to measure cell potential.

Explanation:

The cell potential is the measure of potential difference in the two halves of the electrochemical cell.

It is the measure of how much voltage exists between the two halves of the battery. The unit of volt is joule/coulomb. The cell potential is measured by voltmeter.

The energy per unit charge from the oxidation-reduction reaction to drive the reaction is cell potential.

3 0
3 years ago
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