Answer:
The size of the force developing inside the steel rod is 32039.28 N
Explanation:
Given;
length of the steel rod, L = 1.55 m
cross sectional area of the steel, A = 4.89 cm²
temperature change, ∆T = 28.0 K
coefficient of linear expansion for steel, α = 1.17 × 10⁻⁵ 1/K
Young modulus of steel, E = 200.0 GPa.
Extension of the steel is given as;
α ∆T L = FL / AE
α ∆T = F/AE
F = AEα ∆T
F = ( 4.89 x 10⁻⁴)(200 x 10⁹)(1.17 × 10⁻⁵)(28.0 K)
F = 32039.28 N
Therefore, the size of the force developing inside the steel rod when its temperature is raised, is 32039.28 N
r = distance of moon from earth = 3.84 x 10⁸ m
R = size of the object on moon = 0.67 m
D = diameter of the lens = ?
= wavelength of light = 550 x 10⁻⁹ m
Using the equation for Rayleigh criterion
R/r = 1.22
/D
inserting the values
0.67/(3.84 x 10⁸) = 1.22 (550 x 10⁻⁹) /D
D = 384.6 m
Explanation:
Both galaxies show bicones of high ionisation gas extending along their minor axes. In NGC 4676A the high gas velocity .
please. follow. me
Answer:

Explanation:
From the question we are told that:
Mass of fish 
Cross-sectional area 
Drag coefficient of 
Seawater density 
Speed of Fish
Generally the equation for Drag force F_d is mathematically given by

Generally the equation for high speed Power
is mathematically given by


