Answer:
speed =wavelenght x frequency
v=4.5 x 10 to the -7 x 667=0.3 x 10 to the -4 m/s
speed= distance/time
time=distance/speed
t=4 x 10 to the 16/0.3 x 10 to the -4=13.33 x 10 to the 20 seconds
Explanation:
Answer:
Slope is calculated using the equation: slope= rise/run (y/x). Take take y value of a point and put it over the x value of the same point and then simplify the fraction.
Explanation:
P1.5.3 thats what i got........... hope its right not sure though
Answer:
Potential energy of the object will be equal to mgh
Explanation:
Let the mass of the object is m
Acceleration due to gravity is 
Let the object is released from height h
We have to find the potential energy
Potential energy is of an object released from height h is equal to
, here m is mass, g is acceleration due to gravity and h is height from which object is released.
Answer:
a) 103.32 m
b) 9.18 s
Explanation:
a) Let's use the knowledge that at the top of its trajectory, the baseball will have a final velocity of 0 m/s.
The acceleration due to gravity is -9.8 m/s², assuming the upwards direction is positive and the downwards direction is negative.
The initial velocity of the baseball is 45 m/s.
We are trying to find the vertical displacement of the baseball, Δx, and we have the variables v, a, and v₀.
Find the constant acceleration equation that contains all four of these variables:
Substitute the known values into the equation.
- (0)² = (45)² + 2(-9.8)Δx
- 0 = 2025 - 19.6Δx
- -2025 = -19.6Δx
- Δx = 103.32
The maximum height of the ball before it falls back down is 103.32 m.
b) Now we want to solve for time t. Find a constant acceleration equation that contains three known variables.
Substitute known values into this equation.
- 0 = 45 + (-9.8)t
- -45 = -9.8t
- t = 4.59183673
Remember that this is only half of the baseball's flight since we are using the final velocity for when the ball is halfway through its trajectory.
To solve for the total time the baseball is in the air, double the time t we solved for.
The baseball is in the air for 9.18 s.
