Answer:
(d) I and III
Explanation:
Motion of the 1st light ball
I. Since the heavier starts with an initial velocity v0, and both balls end up traveling the same distance s. From the 2 motion equation above we can conclude that their time must be different
II. Both balls are affected by the same gravitational acceleration g
III. Velocity before the impact of the light ball
And the heavy ball
Since they have the same acceleration g and distance s. But the heavy ball has an initial push. It would end up with a larger speed.
Answer
given,
mass of ball, m = 57.5 g = 0.0575 kg
velocity of ball northward,v = 26.7 m/s
mass of racket, M = 331 g = 0.331 Kg
velocity of the ball after collision,v' = 29.5 m/s
a) momentum of ball before collision
P₁ = m v
P₁ = 0.0575 x 26.7
P₁ = 1.535 kg.m/s
b) momentum of ball after collision
P₂ = m v'
P₂ = 0.0575 x (-29.5)
P₂ = -1.696 kg.m/s
c) change in momentum
Δ P = P₂ - P₁
Δ P = -1.696 -1.535
Δ P = -3.231 kg.m/s
d) using conservation of momentum
initial speed of racket = 0 m/s
M u + m v = Mu' + m v
M x 0 + 0.0575 x 26.7 = 0.331 x u' + 0.0575 x (-29.5)
0.331 u' = 3.232
u' = 9.76 m/s
change in velocity of the racket is equal to 9.76 m/s
Answer:
hello your question is incomplete below is the missing part
Ex = 0
Ey = 
Explanation:
Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π
Ex = 0
Ey =
Answer:
D. Perfectly inelastic
Explanation:
Kinetic energy is lost so the two bodies stick together.
