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malfutka [58]
3 years ago
13

According to the US Census, the percent of residents aged 65 or older in the 50 states and District of Columbia has mean 13.26%

and standard deviation of 1.67% Find and interpret the standardized score for the state of Colorado, which had 9.7% of residents age 65 or older.
Mathematics
1 answer:
Over [174]3 years ago
5 0

Answer:

z = -2.13

The standardized score for the state of Colorado is negative and this means the score is smaller than the mean.

Step-by-step explanation:

The above question can be solved using z score.

The formula for z score is given as:

z = (x-μ)/σ,

where

x is the raw score = 9.7%

μ is the population mean = 13.26%

σ is the population standard deviation = 1.67%

z = z score or standardize score

Hence,

z = 9.7 - 13.26/1.67

z = -2.13174

Approximately z = -2.13

Therefore, the standardized z score for the state of Colorado is negative and this indicates that the score is below or smaller than the mean.

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Answer:

P(16.5

And using the normal standard table or excel we find the probability:

P(-1.768< Z< 1.768) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the avergae number of weeks an individual is unemployed of a population, and for this case we know the distribution for X is given by:

X \sim N(17.5,4)  

Where \mu=17.5 and \sigma=4

Since the distribution for X is normal then, the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu= 17.5, \frac{\sigma}{\sqrt{n}}= \frac{4}{\sqrt{50}}=0.566)

We select a sample of n =50 people. And we want to find the following probability

P(16.5

And using the normal standard table or excel we find the probability:

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