1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
12345 [234]
3 years ago
12

Breaking a solid reactant into pieces results in

Chemistry
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

If one of the reactants is a solid, only the particles at the surface can partake in the reaction. Breaking the reactant into smaller pieces increases the surface and more particles are exposed to the reaction mixture. This results in an increased frequency of collisions and therefore a faster rate of reaction

You might be interested in
A 12.8-g sample of sodium completely reacts with 19.6 g of chlorine to form 32.4 g of sodium chloride. These data are A 12.8-g s
coldgirl [10]

Answer: The data are consistent with the law of conservation of mass because the mass of reactants equals the mass of products

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Given: mass of sodium = 12.8 g

mass of chlorine = 19.6 g

mass of reactants = mass of sodium + mass of chlorine = 12.8 g + 19.6 g = 32.4 g

Mass of product = Mass of sodium chloride = 32.4 g

As mass of reactant = mass of products , Thus results are in accordance with the law of conservation of mass.​

5 0
3 years ago
1.
Jet001 [13]

Answer:

1 mol SO2 contains 6.0213*10^23 molecules

6.023*10^24 molecules = 10 mol SO2

Equation

S(s) + O2(g) → SO2(g)

1 mol S reacts with 1 mol O2 to prepare 1 mol SO2

To prepare 10 mol SO2 you require : 10 mol S plus 10 mol O2

And that is the answer to the question

If you want a mass :

Molar mass S = 32 g/mol You require 10 mol = 320 g

Molar mass O2 = 32 g/mol :You require 10 mol = 320 g

6 0
3 years ago
Read 2 more answers
What is the mass in grams of KBr in 0.400 L of a 0.350 M solution???
melamori03 [73]

Answer:

The answer to your question is: 16.7 g of KBr

Explanation:

Data

mass KBr = ? g

Volume = 0.400 L

Concentration = 0.350 M

Formula

Molarity = moles / volume

moles = molarity x volume

Process

moles = (0.350)(0.400)

          = 0.14

MW KBr = 39 + 80 = 119 g

                                  119 g of KBr --------------------  1 mol

                                   x                 --------------------   0.14 mol

                                   x = (0.14 x 119) / 1

                                   x = 16.7 g of KBr

8 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL MARK YOU BRAINLIEST !!If you react 4.25 moles of FeCl2, how many moles of Cl2 did you also react?
Ksju [112]
Lol yeah that’s what I’m doing I just want you know I got a lot of you guys to go and you don’t get
7 0
3 years ago
When calcium metal (Ca) reacts with oxygen gas (O2), it produces the ionic compound calcium oxide (CaO). Write the balanced equa
jonny [76]

Oxidation-Reduction Reactions Suggested Reading Thus the oxidation number for oxygen in calcium oxide is -2. ... In effect, each calcium atom loses two electrons to form Ca2+ ions, and each O atom in O2 gains two electrons to form O2- ions. The net result is a transfer of electrons from calcium to oxygen, so this reaction is an oxidation-reduction reaction.

+<u>O²</u><u>(</u><u>g</u><u>)</u><u>=</u><u>2</u><u>CaO</u><u>(</u><u>s</u><u>)</u>

Explanation:

we can conclude that in the reaction there is both reduction and oxidation.

6 0
3 years ago
Other questions:
  • It takes to break an carbon-chlorine single bond. Calculate the maximum wavelength of light for which an carbon-chlorine single
    8·1 answer
  • A ball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. Ignoring air resistance, ho
    13·2 answers
  • Provide at least three reasons why friction is needed.
    9·2 answers
  • How many molecules of HCl are needed to react with 1.7 moles of magnesium. The products of
    13·1 answer
  • If I start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, what is the limiting reactant?
    10·1 answer
  • Help please and thank you
    12·1 answer
  • Can someone help me... I need to talk to someone
    14·1 answer
  • How much heat is needed for the decomposition of 168.4 g of sodium nitride into nitrogen and sodium? Your answer should have 4 s
    11·1 answer
  • Name the gas that the limewater in the flask is testing for.
    13·1 answer
  • Hellpppppppppppppppppppppp
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!