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VMariaS [17]
3 years ago
14

5.) Divide 44,100 by 900 =​

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0

Answer:

49

Step-by-step explanation:

44100/900=49

gregori [183]3 years ago
3 0
49 just use a Calculator
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4. Mr. Downey used the function f(x) = -3x2 + 12x to model the flight of a glider. In Mr. Downey's
tankabanditka [31]

Answer: 120 seconds

Step-by-step explanation: In order to find the maximum value of a function, you can take the derivative of the function and equalize the result to 0.

f'(x)=(-3x^2 + 12x)'=-6x+12=0

x=2

When x is 2, the function will reach its maximum value.

f(2)=-3(2)^2 + 12.2 = -12 + 24 = 12

The maximum value (f(x)) is equal to 12 and the time passed is 2 minutes which is equal to 120 seconds.

6 0
3 years ago
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Write 4 216 in expanded form
joja [24]

Answer:

4000+200+10+6

Step-by-step explanation:

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Find the equation of the line parallel to -5x+2y=12 and through (10,21)
Ksivusya [100]

y=5/2x-4

Step-by-step explanation:

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3 years ago
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Find the total area of a cylinder whose radius is 2 cm and height is 4 cm.
kolezko [41]

Answer:

78.95cm^2

Step-by-step explanation:

The equation for a cylinder is rπ^2 · h

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4 0
3 years ago
two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat
Harlamova29_29 [7]

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : v=\frac{distance}{time}. Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

v\,*\,24\,min=d_A

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

v\,*\,32\,min=d_A+5\,miles

Now we solve for d_A in this last equation and make the substitution in the equation for car A:

v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}

So this is the speed of both cars: 0.625 miles/minute

3 0
3 years ago
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